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3 years ago

I need help with my Essay about tectonic plate

Chemistry

1 answer:

JulijaS [17]3 years ago

8 0

use essay bot it will make your essay, and no copying from other cites. And it also sites the sources.

PLZZ BRAINIEST

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A sugar cube was placed into a beaker containing 100 mL of water at room temperature and completely dissolved into the water. Th

Bad White [126]

Answer:

Boil the water until it evaporates

Explanation:

If the water evaporates the sugar will no longer bond to it and then percipitate at the bottom of the beaker.

3 0

3 years ago

BRAINLIESTTT ASAP!! PLEASE ANSWER!!! :)

Arada [10]

Answer:

Redox but not combustion

Explanation:

2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g)

This is a redox reaction, because the oxidation number of K increases from 0 to +1, while that of H decreases from +1 to 0.

It is not a combustion reaction, because combustion is the reaction

with O₂.

The equation for the combustion of potassium would be

4K(s) + O₂(g) ⟶ 2K₂O(s)

7 0

3 years ago

Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.Express your answer to two significant f

N76 [4]

The question is incomplete, here is the complete question:

Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction

A + 2B ⇔ C

whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:

The table is attached below as an image.

Answer: The initial rate for the formation of C at 25°C is $2.25\times 10^{-2}Ms^{-1}$

Explanation:

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+2B\rightleftharpoons C$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b$

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first trial:

$5.4\times 10^{-3}=k(0.30)^a(0.050)^b$ ....(1)

Expression for rate law for second trial:

$1.1\times 10^{-2}=k(0.30)^a(0.100)^b$ ....(2)

Expression for rate law for third trial:

$2.2\times 10^{-2}=k(0.50)^a(0.050)^b$ ....(3)

Dividing 2 by 1, we get:

$\frac{1.1\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.30)^a(1.00)^b}{(0.30)^a(0.050)^b}\\\\2=2^b\\b=1$

Dividing 3 by 1, we get:

$\frac{2.2\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.50)^a(0.050)^b}{(0.30)^a(0.050)^b}\\\\4.07=2^a\\a=2$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^1$ ......(4)

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$5.4\times 10^{-3}=k[0.30]^2[0.050]^1\\\\k=1.2M^{-2}s^{-1}$

Calculating the initial rate of formation of C by using equation 4, we get:

$k=1.2M^{-2}s^{-1}$

[A] = 0.50 M

[B] = 0.075 M

Putting values in equation 4, we get:

$\text{Rate}=1.2\times (0.50)^2\times (0.075)^1\\\\\text{Rate}=2.25\times 10^{-2}Ms^{-1}$

Hence, the initial rate for the formation of C at 25°C is $2.25\times 10^{-2}Ms^{-1}$

8 0

3 years ago

What pressure would a gas exert at absolute zero?Explain

valina [46]

The term absolute zero is given because the volume and the temperature comes to 0. So according to Charles law,
At const K temp, Volume is proportional to Temperature. So the volume is also 0. P = nRT/V. T=0 and P=0

7 0

3 years ago

GUYS HELPPPP PLEASEEE!!!!!!

Vladimir79 [104]

C is your best bet sir

7 0

3 years ago