Answer:
Explanation:
1.). A pure substance has a/an ___definite____ composition.
Pure substances have a definite composition and all their parts are same throughout.
2.). A/An ___mixture____ is composed of two or more types of matter that can be present in varying amounts.
Mixture is a blend of two or more types of matter.
3.). A solution is a/an ___homogeneous ____ mixture.
Solutions are homogeneous mixtures of solutes and solvents.
4.). A mixture that is not uniform throughout is a/an ___heterogeneous ____ mixture.
A mixture that is not uniform throughout is said to be heterogeneous.
5.). A pure substance that cannot be broken down chemically is a/an _______.
An element : is a distinct substance that cannot be split-up into simpler substances.
6.). A characteristic of matter that’s not associated with a change in its chemical composition is known as a/an __physical_____ property.
Physical property tells us everything about what a substance is when no change is occuring to its constituents.
7.).Wax melting is an example of a/an ___physical change____ change in the state of matter.
Physical change is one that alters the physical properties of matter.
8.). A banana peel turning brown is an example of a/an ___chemical____ change in the state of matter.
Chemical change is one in which a new matter is formed.
Answer:
The amount of salt in the tank at the end of an additional 10 minutes are 4.38lb.
Explanation:
<u>Situation 1:</u>
Tank with 100 gallons of fresh water
<u>Situation 2:</u>
Tank with 100 gallons of fresh water + water with 0.5lb of salt per gallon
After 10 minutes, as the rate in which the new water is poured is 2 gallons per minute, the result is 20 gallons added (2×10=20) . And taking in account that the water contains 0.5 lb of salt per gallon the amount of salt added is 20×0.5= 10lb of salt.
That amount of salt is now in all the water inside the tank which is 100 gallons+ 20 gallons= 120 gallons. <em>That means that in situation 2 we have 10lb of salt in 120 gallons of water.</em>
That mixture is allowed to leave the tank at a rate of 2 gallons per minute so we will have after 10 minutes: 120 gallons- (2×10) gallons= 100 gallons remaining in the tank. And the amount of salt if we remember that we had 10lb in 120 gallons, now in 100 gallons we will have: (100 gallons × 10lb of salt)/ 120 gallons= 8.33 lb of salt.
<u>Situation 3:</u>
Tank with 100 gallons of water with 8.33lb of salt.
After 10 minutes in which fresh water is poured in the tank at a rate of 9 gallons per minute, the result is: 9×10= 90 gallons added to the tank. So now we have 100+90=190 gallons of water in the tank. <em>That means in situation 3 we have 8.33 lb of salt in 190 gallons of water. </em>
That mixture is leaving the tank at a rate of 9 gallons per minute so we have after 10 minutes: (190- (9×10))= 100 gallons of mixture remaining in the tank.
And the amount of salt if we remember that we had 8.33lb in 190 gallons, now in 100 gallons we will have: (100 gallons × 8.33lb of salt)/ 190 gallons= 4.38 lb of salt.
Kw = 1 x 10⁻¹⁴
<span>Kw = [ H₃O⁺] [ OH⁻]
</span>
1 x 10⁻¹⁴ = [ H₃O⁺] * 4 x 10⁻³
[H₃O⁺] = 1 x 10⁻¹⁴ / 4 x 10⁻³
[H₃O⁺] = 2.5 x 10⁻¹² M
hope this helps!
False , it will make it lighter
Answer:
47.36mL
Explanation:
Using Boyles law equation, which states that:
P1V1 = P2V2
Where;
V1 = initial volume (mL)
V2 = final volume (mL)
P1 = initial pressure (atm)
P2 = final pressure (atm)
Based on the provided information, V1 = 25.3mL, P1 = 152 kPa, V2 = ?, P2 = 0.804atm
First, we need to convert 152kPa to atm by dividing by 101
1kPa = 0.0099atm
152kPa = 1.505atm
P1V1 = P2V2
1.505 × 25.3 = 0.804 × V2
38.08 = 0.804V2
V2 = 38.08/0.804
V2 = 47.36mL