Answer:
Time interval;Δt ≈ 37 seconds
Explanation:
We are given;
Angular deceleration;α = -1.6 rad/s²
Initial angular velocity;ω_i = 59 rad/s
Final angular velocity;ω_f = 0 rad/s
Now, the formula to calculate the acceleration would be gotten from;
α = Change in angular velocity/time interval
Thus; α = Δω/Δt = (ω_f - ω_i)/Δt
So, α = (ω_f - ω_i)/Δt
Making Δt the subject, we have;
Δt = (ω_f - ω_i)/α
Plugging in the relevant values to obtain;
Δt = (0 - 59)/(-1.6)
Δt = -59/-1.6
Δt = 36.875 seconds ≈ 37 seconds
Answer:
An airplane flying
Explanation:
Both a bird and airplane fly, but the airplane is using more mechanical energy to run and power the plane, causing it to fly.
If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects
<u>Answer:</u>
increases
Explanation:
The formula of gravitational force is given as:
F=G Mm/r^2
G = gravitational constant
M, m = Masses of two different objects in which the force is acting.
r = distance between both the objects.
As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.
When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.
Illamends had the exact same answer from a similar question. Credit goes to her
Answer:
the molrcular mass of carbon dioxide id 44.01amu
Explanation:
plz make me brainliest
Answer:
Part a)

Part b)

Part d)
As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different
On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.
Explanation:
Part a)
By Guass law we know that



Part b)
Outside the outer cylinder we will again use Guass law



Part d)
As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different
On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.