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3 years ago

The molecular mass of CO2.

Physics

2 answers:

sasho [114]3 years ago

8 0

Answer:

44.01 g/mole (molecular mass)

Explanation:

Hope that helps

mylen [45]3 years ago

4 0

Answer:

the molrcular mass of carbon dioxide id 44.01amu

Explanation:

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select the example that best describes a renewable resource. a. all the houses built in the new neighborhood had natural gas ava

Bad White [126]

B. my town is powered by electricity that is generated by the energy from the flow of water through a large dam.

The water from the large dam is example of renewable energy. It can be replenished through rainfall cycle, so it is a renewable form of energy.

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3 years ago

Read 2 more answers

A uniform log of length L is inclined 30° from the horizontal when supported by a frictionless rock located 0.6L from its left e

mafiozo [28]

Answer:

x = 0.974 L

Explanation:

given,

length of inclination of log = 30°

mass of log = 200 Kg

rock is located at = 0.6 L

L is the length of the log

mass of engineer = 53.5 Kg

let x be the distance from left at which log is horizontal.

For log to be horizontal system should be in equilibrium

∑ M = 0

mass of the log will be concentrated at the center

distance of rock from CM of log = 0.1 L

now,

∑ M = 0

$m_{log} g \times 0.1 L = m_{engineer} g \times (x - 0.6 L)$

$200 \times 0.1 L = 53.5 \times (x - 0.6 L)$

$0.374 L =x - 0.6 L$

x = 0.974 L

hence, distance of the engineer from the left side is equal to x = 0.974 L

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3 years ago

A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.

nikitadnepr [17]

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

momentum of the ball, P = 0.9 kgm/s
weight of the ball, W = 0.14 N

The impulse experienced by the ball is calculated as follows;

$Ft = \Delta P$

where;

$Ft$ is impulse

$\Delta P$ is change in momentum

The time of motion of the ball is calculated as follows;

$t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s$

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

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2 years ago

Figure 10.20 in your textbook shows an energy diagram for a system with total energy E1. Suppose the system's total energy is E2

wolverine [178]

The particles can undergo small oscillations around x₂.

The given parameters;

initial energy of the particles = E₁
final energy of the particles, E₂ = 0.33E₁

The movement of the particles depends on the kinetic energy of the particles.

When kinetic energy of the particles is 100%, the particles can oscillate from x₁ to x₅.

However, when the total energy of this particles is reduced to one-third (¹/₃) or 33% of the initial energy of the particle, the oscillation of the particles will be reduced.

The maximum position the particle can oscillate is x₅

The half position the particles can oscillate is x₃

Since 33% is less than the half of the energy of the particle, the particle will oscillate between x₁ and x₂.

Thus, we can conclude that the particles can undergo small oscillations around x₂.

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3 years ago

47) Which of the following types of energy is the kind that an object gains when it is raised to a higher point on a

butalik [34]

Answer:

kinetic

Explanation:

kinetic energy is powered by motion or gravity the steeper the hill is the faster a ball will roll

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3 years ago