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3 years ago

Through which material does light move fastest?

Physics

2 answers:

Rom4ik [11]3 years ago

7 0

Answer:

Open Space or B

Explanation:

There is no resistance in space since space is a vacuum.

LiRa [457]3 years ago

3 0

Answer:

I think the answer is Open Space

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Which of the following is the equation for calculating daily caloric needs? A. BMR calories + Digestion calories B. BMR calories

labwork [276]

Explanation:

To determine your total daily calorie needs, multiply your BMR by the appropriate activity factor, as follows: If you are sedentary (little or no exercise) : Calorie-Calculation = BMR x 1.2. If you are lightly active (light exercise/sports 1-3 days/week) : Calorie-Calculation = BMR x 1.375.

<em><u>HAPPY TO HELP</u></em>

8 0

3 years ago

Read 2 more answers

Como se dice casa en náhuatl

NNADVOKAT [17]

La respuesta es Chantli

4 0

3 years ago

When a 0.350-kg package is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The package is now di

AleksandrR [38]

To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.

We know that by Hooke's law

$F=kx$

Where,

k = Spring constant

x = Displacement

Re-arrange to find k,

$k= \frac{F}{x}$

$k= \frac{mg}{x}$

$k= \frac{(0.35)(9.8)}{12*10^{-2}}$

$k = 28.58N/m$

Perioricity in an elastic body is defined by

$T = 2\pi \sqrt{\frac{m}{k}}$

Where,

m = Mass

k = Spring constant

$T = 2\pi \sqrt{\frac{0.35}{28.58}}$

$T = 0.685s$

Therefore the period of the oscillations is 0.685s

4 0

3 years ago

A 55.6 kg ice skater is moving at 1.73 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.

GarryVolchara [31]

Answer:

The force exerted by the rope on her arms is 273.7 N = 0.274 kN

Explanation:

Step 1: Data given

Mass of the ice skater = 55.6 kg

Velocity = 1.73 m/s

She then moves in a circle of radius 0.608 m around the pole.

Step 2:

Force exterted by the horizontal rope is the centripetal force acting on theice skater:

Fc = M*ac

⇒ with ac = v²/r

Fc = M * v²/r

Fc = 55.6 * 1.73²/0.608

Fc =273.69 N

The force exerted by the rope on her arms is 273.7 N = 0.274 kN

7 0

3 years ago

Assume that the system has zero gravitational potential energy at the lowest point of the motion. Derive an expression for the t

tatuchka [14]

Answer:

See explanation

Explanation:

From what I can see in the question, there is a monkey of mass m suspened at the end of a spring which constant is k and this monkey has moved a distance d.

The mechanical energy for the situation will be composed of elastic potential energy from the spring, kinetic energy from the monkey and potential gravitational energy from the monkey as well.

$E = K_{monkey} + U_{monkey} + U_{spring}\\E= \frac{mv_{e}^2}{2} + mgd + \frac{kx^2}{2}$

where m is the monkey's mass, $v_{e}$ is the speed of the monkey, d is the distance that the monkey has moved, k is the spring constant and x is the distance that the spring has stretched

8 0

3 years ago