2 years ago

2 (e+4) = 8e-20find the variable

1 answer:

6 0

Distribute the 2 on the left to get 2e + 8 = 8e - 20 Add 20 to both sides and subtract 2e from both sides. 28 = 6e Divide both sides by 6. e = 14/3

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Answer:

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Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

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so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

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Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

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