Plug in 7 for x and 24 for v
MP and MN that's angle M
answer
m<M
The smallest possible product of these four numbers is 59.0625
<h3>How to find the smallest possible product of these four numbers?</h3>
The equation is given as:
a + b + c + d = 12
The numbers are consecutive numbers.
So, we have:
a + a + 1 + a + 2 + a + 3 = 12
Evaluate the like terms
4a = 6
Divide by 4
a = 1.5
The smallest possible product of these four numbers is represented as:
Product = a * (a + 1) * (a + 2) * (a + 3)
This gives
Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)
Evaluate
Product = 59.0625
Hence, the smallest possible product of these four numbers is 59.0625
Read more about consecutive numbers at:
brainly.com/question/10853762
#SPJ1
Answer:
kevin = 8 - hope this helped
:)
Step-by-step explanation:
Kevin = 4d Kevin is 4 times as old as Daniel
Kevin = d + 6 Kevin is 6 years older than Daniel
4d = d + 6 They both equal K, so they are equal
3d = 6 subtracts D from both sides
d=6/3 = 2
If Daniel is 2 then Kevin is 4x2=8
If Daniel is 2 then Kevin is 2+6 = 8
Kevin is 8
Daniel is 2
1. 3x - 2y = 8 Subtract 3x on both sides
-2y = 8 - 3x Divide by -2 on both sides to get y by itself
y = -4 + 3/2x
2. a + b / 3 = 5 Multiply 3 on both sides
a + b = 15 Subtract a on both sides to get b by itself
b = 15 - a
3. 12x - 4y = 20 Subtract -12x on both sides
-4y = 20 - 12x Divide -4 on both sides to get y by itself
y = -5 + 3x
4. y + 3 = -5(x - 2) Multiply -5 to (x-2)
y + 3 = -5x + 10 Subtract 3 on both sides to get y by itself
y = -5x + 7
