Answer:
The experimental scientist
Answer:
v = 306.76 Km/h
Explanation:
given,
height of the aircraft = 3000 m
differential pressure reading = 3300 N/m²
density of air = 0.909 Kg/m³
speed of aircraft = ?
Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.
using Bernoulli's equation

where ρ is the density of the air at 3000 m



v = 85.21 m/s

v = 306.76 Km/h
Answer: 74.8m
Explanation:
We have the vector defined by:
r = 101m
θ = 42.2°
When we want to write this as rectangular components, we have that:
x = r*cos(θ)
y = t*sin(θ)
this is because we can construct a triangle rectangle, where the module of the vector is the hypotenuse, the x component is the adjacent cathetus and the y component is the opposite cathetus.
Then, here we have that the x component is
x = 101m*cos(42.2°) = 74.8m
Complete Question
An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by parallel lines drawn with a density N lines per m2 that are perpendicular to and away from the sheet. The charge per unit area on the sheet is doubled. How should the density of the electric field lines be changed?
A It should stay the same
B It should be quadrupled.
C It should be quintupled
D It should be doubled.
E It should be tripled
Answer:
Option D is the correct option
Explanation:
Generally electric field is mathematically represented as

Where
is the charge per unit area (Charge density )
From the question we are told that
is doubled hence the
Looking the equation above we see that the value of the electric field will also double given that it is directly proportional to the charge density
Answer:
They are equal
Explanation:
Multiply the mass by the velocity.