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Maksim231197 [3]
4 years ago
7

Gravitational Force: Two small objects, with masses m and M, are originally a distance r apart, and the magnitude of the gravita

tional force on each one is F. The masses are changed to 2m and 2M, and the distance is changed to 4r. What is the magnitude of the new gravitational force?
Physics
1 answer:
Alona [7]4 years ago
4 0

Law of universal gravitation:

F = GMm/r²

F = gravitational force, G = gravitational constant, M & m = masses of the objects, r = distance between the objects

F is proportional to both M and m:

F ∝ M, F ∝ m

F is proportional to the inverse square of r:

F ∝ 1/r²

Calculate the scaling factor of F due to the change in M:

k₁ = 2M/M = 2

Calculate the scaling factor of F due to the change in m:

k₂ = 2m/m = 2

Calculate the scaling factor of F due to the change in r:

k₃ = 1/(4r/r)² = 1/16

Multiply the original force F by the scaling factors to obtain the new force:

Fk₁k₂k₃

= F(2)(2)(1/16)

= F/4

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A scientist that applies the laws of science to the needs of communities is called _____.
s2008m [1.1K]

Answer:

The experimental scientist

5 0
3 years ago
A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3300
adell [148]

Answer:

   v = 306.76 Km/h

Explanation:

given,

height of the aircraft = 3000 m

differential pressure reading = 3300 N/m²

density of air = 0.909 Kg/m³

speed of aircraft = ?

Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.

using Bernoulli's equation

          \dfrac{v^2}{2} = \dfrac{\Delta P}{\rho}

where ρ is the density of the air at 3000 m

          v= \sqrt{\dfrac{2 \times \Delta P}{\rho}}

          v= \sqrt{\dfrac{2 \times 3300}{0.909}}

          v = \sqrt{7260.726}

                 v = 85.21 m/s

          v= 85.21 \times \dfrac{3600}{1000}

                 v = 306.76 Km/h

4 0
3 years ago
Find the x-component of this
Sholpan [36]

Answer: 74.8m

Explanation:

We have the vector defined by:

r = 101m

θ = 42.2°

When we want to write this as rectangular components, we have that:

x = r*cos(θ)

y = t*sin(θ)

this is because we can construct a triangle rectangle, where the module of the vector is the hypotenuse, the x component is the adjacent cathetus and the y component is the opposite cathetus.

Then, here we have that the x component is

x = 101m*cos(42.2°) = 74.8m

5 0
3 years ago
An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by p
nexus9112 [7]

Complete Question

An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by parallel lines drawn with a density N lines per m2 that are perpendicular to and away from the sheet. The charge per unit area on the sheet is doubled. How should the density of the electric field lines be changed?

A It should stay the same

B  It should be quadrupled.

C It should be quintupled

D It should be doubled.

E It should be tripled

Answer:

Option D is the correct option

Explanation:

Generally electric field is mathematically represented as

        E =  \frac{\sigma}{\epsilon_o}

Where \sigma is the charge per unit area (Charge density )

From the question we are told that \sigma is doubled hence the

     E =  \frac{2 \sigma }{\epsilon_o}    

Looking the equation above we see that the value of the electric field will also double given that it is directly proportional to the charge density

8 0
3 years ago
18. Compare the momentum of a 5450 kg truck moving at 8.00 m/s to the momentum of a 2725 kg car moving at 16.0 m/s.​
avanturin [10]

Answer:

They are equal

Explanation:

Multiply the mass by the velocity.

6 0
3 years ago
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