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WINSTONCH [101]
4 years ago
15

The shorter the the wavelength the blank frequency

Physics
2 answers:
zhenek [66]4 years ago
8 0

Answer:

Higher the frequency is

Explanation:

The longer the wavelength the lower the frequency

slega [8]4 years ago
3 0

Answer:the shorter the wavelength, the bigger then they frequency

Explanation:

the shorter the wavelength,the bigger the frequency

Frequency is inversely proportional to wavelength

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A planet has a surface temperature of 95.0 K and an atmospheric pressure of 1.60 atm. If 4.87 L of atmosphere has a mass of 28.6
mr Goodwill [35]

Answer:

M=28.88 gm/mol

Explanation:

Given that

T= 95 K

P= 1.6 atm

V= 4.87 L

m = 28.6 g

R=0.08206L atm .mol .K

We know that gas equation for ideal gas

P V = n R T

P=Pressure , V=Volume ,n=Moles,T= Temperature ,R=gas constant

Now by putting the values

P V = n R T

1.6 x 4.87  = n x 0.08206 x 95

n=0.99 moles

We know that number of moles given as

n=\dfrac{m}{M}

M=Molar mass

n=\dfrac{m}{M}

0.99=\dfrac{28.6}{M}

M=28.88 gm/mol

3 0
3 years ago
What does the horizontal line through the center of the wave on a graph represent?
aleksandrvk [35]

Answer:

This is the midline or the medium which is the exact middle of the graphs minimum and maximum points(which are the amplitude)

8 0
3 years ago
What is the atmospheric pressure of the U.S.
rusak2 [61]
When you say atmospheric pressure it is a standard on all places on earth. The value of standard atmospheric pressure is 1 Bar approximately or 14.7 lb per square inch. This pressure is an attribute of free molecules on the air which is not bound the accumulation of the pressure of this in average is the atmospheric pressure.
4 0
3 years ago
Which of these is an example of interference? A. two lasers pointing away from each other В. two different light waves colliding
iren2701 [21]

Answer:

I believe the answer is B. Although it might be C.

Explanation:

I hope this helps!

6 0
3 years ago
Please help An object is observed to move under the following equation of motion ... x(t) = A√t ... take A =√2. Determine the eq
tatuchka [14]

Explanation:

Function of distance w.r.t time :

x(t) = \: y =   \sqrt{2t}

Differentiate w.r.t time to get velocity :

\frac{dy}{dt}  = v =  \frac{1}{ \sqrt{2t} }

Differentiate w.r.t time to get Acceleration :

\frac{d^2y}{dx^2}  = a \:  =  -  \frac{1}{2t \sqrt{2t} }

3 0
4 years ago
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