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andrey2020 [161]
3 years ago
7

For a specific enzyme/substrate system, which condition will always result in an increase in Vo (assuming nothing else changes)?

Chemistry
1 answer:
inessss [21]3 years ago
8 0
<span>a decrease in Km and an increase in Vmax
 km is the constant that relates how thick the volume of the substrate in terms of concentration when the speed is a large portion of the most extreme. They increment Km by meddling with the joining process that makes them stick together wit the substrate, however they have any effect with regards to Vmax since since the sticking process to ES did not occur</span>
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Is each of the following a physical or chemical property? ● melting point ● ability to react ● color ● density ● ability to burn
ryzh [129]
These are definitely chemical properties
5 0
3 years ago
What is the chemical name for the balanced equation? 2Al+3Pb(NO3)2=2Al(NO3)3+3Pb​
Zigmanuir [339]
  • The chemical name for reactant side:

                  Al - Aluminium, Pb(NO3)2 -  Lead(II) nitrate.

  • The chemical name for product side:

                  Al(NO3)3 - Aluminium nitrate, Pb - lead.

<u>Explanation</u>:

  • This is an oxidation-reduction (redox) reaction:

                       3 Pb^{II} + 6 e- → 3 Pb^{o} (reduction)

                       2 Al^{o} - 6 e- → 2 Al^{III} (oxidation)

Pb(NO3)2 is an oxidizing agent, Al is a reducing agent.

  • Reactants:                              

                                    Al uminium

              Names: Aluminum, Aluminium powder,  Al

              Appearance: Silvery-white-to-grey powder, Silvery-white,  

                                      malleable, ductile, odorless metal.

                             Pb(NO3)2 – Lead(II) nitrate

              Other names: Lead nitrate, Plumbous nitrate, Lead dinitrate

              Appearance: White colorless crystals,  White or colorless crystals

  • Products:

                            Al(NO3)3 – Aluminium nitrate

              Other names: Nitric Aluminum salt, Aluminum nitrate,

                                       Aluminium(III) nitrate

              Appearance: White crystals, solid | hygroscopic

                                   Pb  - lead

              Names: Lead, Lead metal, Plumbum

              Appearance: Bluish-white or silvery-grey solid in various forms.

                                     Turns tarnished on exposure to air. A heavy, ductile,

                                     soft, gray solid.

8 0
3 years ago
Why it’s possible to walk through air but not a concrete wall
Sunny_sXe [5.5K]

well you can't walk through the air but you can't walk through a concrete wall because all of the solid atoms holding it together

3 0
3 years ago
Rank the following elements by effective nuclear charge, Zeff, for a valence electron. F LI Be B N
Stels [109]

Answer:

Rank in increasing order of effective nuclear charge:

  • Li < Be < B < N < F

Explanation:

This explains the meaning of effective nuclear charge, Zeff, how to determine it, and the calculations for a valence electron of each of the five given elements: F, Li, Be, B, and N.

<u>1) Effective nuclear charge definitions</u>

  • While the total positive charge of the atom nucleus (Z) is equal to the number of protons, the electrons farther away from the nucleus experience an effective nuclear charge (Zeff) less than the total nuclear charge, due to the fact that electrons in between the nucleus and the outer electrons partially cancel the atraction from the nucleus.

  • Such effect on on a valence electron is estimated as the atomic number less the number of electrons closer to the nucleus than the electron whose effective nuclear charge is being determined: Zeff = Z - S.

<u><em>2) Z eff for a F valence electron:</em></u>

  • F's atomic number: Z = 9
  • Total number of electrons: 9 (same numer of protons)
  • Period: 17 (search in the periodic table or do the electron configuration)
  • Number of valence electrons:  7 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 9 - 7 = 2
  • Zeff = Z - S = 9 - 2 = 7

<u><em>3) Z eff for a Li valence eletron:</em></u>

  • Li's atomic number: Z = 3
  • Total number of electrons: 3 (same number of protons)
  • Period: 1 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 1 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 3 - 1 = 2
  • Z eff = Z - S = 3 - 2 = 1.

<em>4) Z eff for a Be valence eletron:</em>

  • Be's atomic number: Z = 4
  • Total number of electrons: 4 (same number of protons)
  • Period: 2 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 2 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 4 - 2 = 2
  • Z eff = Z - S = 4 - 2 = 2

<u><em>5) Z eff for a B valence eletron:</em></u>

  • B's atomic number: Z = 5
  • Total number of electrons: 5 (same number of protons)
  • Period: 13 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 3 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 5 - 3 = 2
  • Z eff = Z - S = 5 - 2 = 3

<u><em>6) Z eff for a N valence eletron:</em></u>

  • N's atomic number: Z = 7
  • Total number of electrons: 7 (same number of protons)
  • Period: 15 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 5 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 7 - 5 = 2
  • Z eff = Z - S = 7 - 2 = 5

<u><em>7) Summary (order):</em></u>

  Atom          Zeff for a valence electron

  • F                   7
  • Li                   1
  • Be                 2
  • B                   3
  • N                   5

  • <u>Conclusion</u>: the order is Li < Be < B < N < F
6 0
3 years ago
To what volume should 25ml of 15m nitric acid be diluted to prepare a 3m solution
Maurinko [17]

We can use the dilution formula to find the volume of the diluted solution to be prepared

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

15 M x 25 mL = 3 M x v2

v2 = 125 mL

The 25 mL concentrated solution should be diluted with distilled water upto 125 mL to make a 3 M solution

6 0
3 years ago
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