The number of years that will pass before the radius of the Moon's orbit increases by 3.6 x 10^6 m will be 90000000 years.
<h3>How to compute the value?</h3>
From the information given, the orbit of the moon is increasing in radius at approximately 4.0cm/yr.
Therefore, we will convey the centimeters to meter. This will be 4cm will be:
= 4/100 = 0.04m/yr.
Time = Distance / Speed
Time = 3.6 x 10^6/0.04
Time = 90000000 years.
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Complete question:
Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the moon is increasing in radius at approximately 4.0cm/y. Assuming this rate to be constant how many years will pass before the radius of the Moon's orbit increases by 3.6 x 10^6
Answer:
oxygen silicon aluminun iron
Pressure = total force/total area
Total force = 660 Newton's
Total area:
Each leg contacts the floor with an area of πr^2=π(0.025m)^2=0.002m^2.
Total contact area for all 3 legs = 0.006 m^2.
Pressure = (660N) / (0.006 m^2)
= 110,000 N/m^2 = 110,000 Pascal's.
speed=frequency*wavelength, so frequency=speed/wavelength. frequency=80*0.2
Frequency = 16 Hz
