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3 years ago

9

Is the Statue of Liberty a frame structure ?

2 answers:

koban [17]3 years ago

8 0

Yes it is, it was made in France as a gift to the U.S.A.

Anon25 [30]3 years ago

4 0

The Statue of Liberty has iron frame

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All of the planets and their satellites orbit the Sun in the same direction, and all their orbits lie near the same plane. True

MissTica

Answer:

True

Explanation:

The Sun rotates in the counterclockwise (CCW) direction when seen from its north pole. Since, the planets revolve around the Sun because of its gravity, the revolution of all the planets and their moons as seen from the north of the Sun is in CCW direction.

In fact most of the solar system bodies rotate in the same direction that is CCW. Some major exceptions to this are Venus and Uranus.

Almost all the planets and moons were made from the planetary disk around the Sun. Thus, they lie nearly in the same plane.

4 0

3 years ago

16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current d

dsp73

Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t = power X time

W / t = P power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

5 0

2 years ago

wo lacrosse players collide in midair. Jeremy has a mass of 120 kg and is moving at a speed of 3 m/s. Hans has a mass of 140 kg

Julli [10]

2.71 m/s fast Hans is moving after the collision.

<u>Explanation</u>:

Given that,

Mass of Jeremy is 120 kg ( $M_J$ )

Speed of Jeremy is 3 m/s ( $V_J$ )

Speed of Jeremy after collision is ( $V_{JA}$ ) -2.5 m/s

Mass of Hans is 140 kg ( $M_H$ )

Speed of Hans is -2 m/s ( $V_H$ )

Speed of Hans after collision is ( $V_{HA}$ )

Linear momentum is defined as “mass time’s speed of the vehicle”. Linear momentum before the collision of Jeremy and Hans is

= $=\mathrm{M}_{1} \times \mathrm{V}_{\mathrm{J}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{H}}$

Substitute the given values,

= 120 × 3 + 140 × (-2)

= 360 + (-280)

= 80 kg m/s

Linear momentum after the collision of Jeremy and Hans is

= $=\mathrm{M}_{\mathrm{J}} \times \mathrm{V}_{\mathrm{JA}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{HA}}$

= 120 × (-2.5) + 140 × $V_{HA}$

= -300 + 140 × $V_{HA}$

We know that conservation of liner momentum,

Linear momentum before the collision = Linear momentum after the collision

80 = -300 + 140 × $V_{HA}$

80 + 300 = 140 × $V_{HA}$

380 = 140 × $V_{HA}$

380/140= $V_{HA}$

$V_{HA}$ = 2.71 m/s

2.71 m/s fast Hans is moving after the collision.

4 0

3 years ago

sasho [114]

Answer:

The answer is 40 cm.

Explanation:

7 0

3 years ago

Who else got stuck on a question and is NOT ready for test return at 2? its 1:58 AAAAAAA

k0ka [10]

Good luckkkk hope you do well

3 0

3 years ago