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laila [671]
3 years ago
11

What is the specific heat of water? A. 1.00 J/gºC

Physics
1 answer:
Leona [35]3 years ago
7 0

Answer:

B 4.18J\g degree C is the specific heat of water

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Which of the following compounds is not likely to have ionic bonds? Question 5 options: LiF NaCl CH4 MgF2
Harrizon [31]

Answer:

CH4

Explanation:

CH4 is joined together by a covalent bond, aka a bond between two non-metals. Non-metals are found on the right side of the periodic table and include Carbon (C) and Hydrogen. Although Hydrogen is technically on the left side of the table, it has the characteristics of a non-metal. Futhermore, Ionic bonds generally are between an element on the right joined with an element on the left. This is because ionic bonds want charges that will cancel out to create a neutral molecule.

example: LiF

Li→ Li+

F→F-

(Li+)+(F-)=charges cancel out.

7 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

s_A = -6 + 9t

s_B = 5 - 8t

When A an B meets, they are at the same position and at the same time. So

s_A = s_B

-6 +9t = 5 - 8t

17t = 5 + 6 = 11

t = 11/17 = 0.647 s

s_A = -6 + 9*0.647 = -0.176 m

So where they meet is 0.176m from the flagpole, westward.

5 0
3 years ago
Which condition is required for Coulomb's law to hold true?
AleksAgata [21]
The correct answer is:
<span>Point charges must be in a vacuum.

In fact, the usual form for of the Coulomb's law is:
</span>F= \frac{1}{4 \pi \epsilon_0}  \frac{q_1 q_2}{r^2}
<span>where
</span>\epsilon_0 is the permittivity of free space
<span>q1 and q2 are the two charges
q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>F= \frac{1}{4 \pi \epsilon_0 \epsilon_r} \frac{q_1 q_2}{r^2}
where \epsilon_r is the relative permittivity, which takes into account the dielectric effects of the material.
7 0
3 years ago
Consider a physical situation in which a particle moves from point A to point B. This process is described from two coordinate s
Fudgin [204]

Coordinates, displacement

8 0
3 years ago
Read 2 more answers
What is the definition of a solution
Naya [18.7K]

Answer:

a means of solving a problem or dealing with a difficult situation.

Explanation:

5 0
3 years ago
Read 2 more answers
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