Question

e strategy, the y component of the projectile's acceleration, ay, is taken to be negative. This implies that the positive y axis is upward. Use the same convention for your y axis, and take the positive x axis to be to the right. Where you choose your origin doesn't change the answer to the question, but choosing an origin can make a problem easier to solve (even if only a bit). Usually it is nice if the majority of the quantities you are given and the quantity you are trying to solve for take positive values relative to your chosen origin. Given this goal, what location for the origin of the coordinate system would make this problem easiest? As stated in the strategy, choose a coordinate system where the x axis is horizontal and the y axis is vertical. Note that in the strategy, the y component of the projectile's acceleration, , is taken to be negative. This implies that the positive y axis is upward. Use the same convention for your y axis, and take the positive x axis to be to the right. Where you choose your origin doesn't change the answer to the question, but choosing an origin can make a problem easier to solve (even if only a bit). Usually it is nice if the majority of the quantities you are given and the quantity you are trying to solve for take positive values relative to your chosen origin. Given this goal, what location for the origin of the coordinate system would make this problem easiest? At ground level below the point where the rock is launched At the point where the rock is released At the point where the rock strikes the ground At the peak of the trajectory At ground level below the peak of the trajectory

Answer 1

Answer:

The best system : Coordinate system at the launch point

Explanation:

This is a problem of analysis, the objective is to facilitate the calculations, let's see ballast possibilities

- Ground coordinate system

In this case the displacements are all positive, even though there is a song that is the initial displacement (xo, I) that we must add to all the equations,

Vertical speeds are positive in the first part of the trajectory and negative after the maximum point

It may be useful in some cases, but it is not the ideal system for the equations

- Coordinate system at the launch point

In this system all displacements are positive, the initial position is zero, which simplifies the equations a bit

The vertical speed is positive in the first pate of the movement

This is the ideal system since it meets the criteria of the greatest number of positive variables and is the one that most simplifies the equations

this is the best selection

- Coordinate system at the highest point of the trajectory

In this case all X and Y displacements are negative, the velocities on the Y axis are positive before origin and negative after origin,

This system does not meet the criteria of the greatest number of positive variables, so they would be bad choice