One positive affect of recycling aluminum cans to manufacture new beverage containers is

Arachidonic acid and pge1 are both carboxylic acids with atoms. the differences are that arachidonic acid contains and no other

hichkok12 [17]

Answer:
Arachidonic Acid and PGE₁ are both carboxylic acids with Twenty Carbon atoms. The differences are that Arachidonic acid contains Four cis Double Bonds and no other functional groups, whereas PGE₁ has One Trans Double Bond, Two Hydroxyl and One Ketone Functional Groups.. In addition, a part of the PGE₁ chain forms a Five Membered Ring.

Structures of Both Arachidonic Acid and PGE₁ are shown Below,

8 0

3 years ago

Which subatomic particles are found in the

pashok25 [27]

For any element the nucleus consists of neutrons and protons while electrons orbit around the nucleus, (3)

6 0

3 years ago

What is not a guideline required for a valid evidence test?

kirill115 [55]

I just took that quiz , it’s A

4 0

3 years ago

What is the coefficient in this chemical formula? 3C6H12O6

erma4kov [3.2K]

Answer:

C-3

Explanation:

7 0

3 years ago

Read 2 more answers

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179 x 1023 atoms of magnesium with 54.21 g of pho

wlad13 [49]

<h3>Answer:</h3>

18.58 liters of hydrogen gas

<h3>Explanation:</h3>

We are given;

The equation;

3Mg + 2H₃(PO₄) → Mg₃(PO₄)₂ + 3H₂

Atoms of Magnesium = 7.179 x 10^23 atoms
Mass of phosphoric acid as 54.21 g

We are required to determine the volume of hydrogen gas produced;

Step 1; moles of Magnesium

1 mole of an element contains 6.02 × 10^23 atoms

therefore;

Moles of Mg = (7.179 x 10^23 ) ÷ (6.02 × 10^23)

= 1.193 moles

Step 2: Moles of phosphoric acid

moles = Mass ÷ Molar mass

Molar mass of phosphoric acid = 97.994 g/mol

Therefore;

Moles of Phosphoric acid = 54.21 g ÷ 97.994 g/mol

= 0.553 moles

Step 3: Determine the rate limiting reagent

From the mole ratio of Mg to Phosphoric acid (3 : 2);

1.193 moles of magnesium requires 0.795 moles of phosphoric acid while,

0.0553 moles of phosphoric acid requires 0.8295 moles of Mg

Therefore, phosphoric acid is the rate limiting reagent

step 4: Determine the moles of hydrogen produced

From the equation, w moles of phosphoric acid reacts to produce 3 moles of hydrogen;

Therefore; moles of Hydrogen = moles of phosphoric acid × 3/2

= 0.553 moles × 3/2

= 0.8295 moles

Step 5: Volume of hydrogen gas

1 mole of a gas occupies a volume of 22.4 liters at STP

Therefore;

Volume of Hydrogen = 0.8295 moles × 22.4 L/mol

= 18.58 Liters

Therefore; 18.58 liters of hydrogen gas will be produced

4 0

3 years ago