Your boss needs to recommend either the in-situ soil or the borrow material. Although you do not have much background on soil be
havior, what is your recommendation?
In providing your recommendation, you want to consider constructability issues (such as ease of compaction, moisture content). Without doing any additional tests, and based on your experience with soils, what compaction conditions would you suggest to achieve low permeability? What compaction conditions would you recommend to reduce soil expansion (swelling)?
Table 1 Compaction Characteristics of Selected Soils.
Borrow Soil In-Situ Soil
STANDARD MODIFIED STANDARD MODIFIED
PROCTOR PROCTOR PROCTOR PROCTOR
Dry Unit Water Dry Unit Water Dry Unit Water Dry Unit Water
Weight Content Weight Content | Weight Content Weight content
Yd (kN/m³) w(%) Yd (kN/m³) w(%) Yd (kN/m³) w(%) Yd (kN/m³) w(%)
16.68 8.4 17.58 5.7 15.63 12.7 15.72 10.4
18.79 9.7 20.02 7.4 17.72 14.4 18.76 12.2
S3? S3? 20.60 9.3 17.46 16.0 18.64 14.0
18.62 13.4 19.62 11.3 17.15 16.7 18.15 15.0
18.05 15.0 18.93 13.0 16.30 18.2 17.48 16.4
In providing your recommendation, you want to consider constructability issues (such as ease of compaction, moisture content). Without doing any additional tests, and based on your experience with soils, what compaction conditions would you suggest to achieve low permeability? What compaction conditions would you recommend to reduce soil expansion (swelling)?
Table 1 Compaction Characteristics of Selected Soils.
Borrow Soil In-Situ Soil
STANDARD MODIFIED STANDARD MODIFIED
PROCTOR PROCTOR PROCTOR PROCTOR
Dry Unit Water Dry Unit Water Dry Unit Water Dry Unit Water
Weight Content Weight Content | Weight Content Weight content
Yd (kN/m³) w(%) Yd (kN/m³) w(%) Yd (kN/m³) w(%) Yd (kN/m³) w(%)
16.68 8.4 17.58 5.7 15.63 12.7 15.72 10.4
18.79 9.7 20.02 7.4 17.72 14.4 18.76 12.2
S3? S3? 20.60 9.3 17.46 16.0 18.64 14.0
18.62 13.4 19.62 11.3 17.15 16.7 18.15 15.0
18.05 15.0 18.93 13.0 16.30 18.2 17.48 16.4
1 answer:
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Answer:
The population size would be
The yield would be
Explanation:
So in this problem we are going to be examining the application of a population dynamics a fishing pond and stock fishing and objective would be to obtain the maximum sustainable yield and and the population of the fish at the obtained maximum sustainable yield, so basically we would be applying an engineering solution to fishing
So the current yield which is mathematically represented as
Where dN is the change in the number of fish
and dt is the change in time
So in order to obtain the solution we need to obtain the rate of growth
For this we would be making use of the growth rate equation which is
Where N is the population of the fish which is given as 4,000 fishes
and K is the carrying capacity which is given as 10,000 fishes
r is the growth rate
Substituting these values into the equation
The maximum sustainable yield would be dependent on the growth rate an the carrying capacity and this mathematically represented as
So since the maximum sustainable yield is 2082 then the the population need to be higher than 4,000 so in order to ensure a that this maximum yield the population size denoted by would be