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Elanso [62]
3 years ago
11

How many types of residential circuits are There A. 4 B. 3 C. 5 D. 7

Engineering
2 answers:
gulaghasi [49]3 years ago
5 0

<u>Answer:</u>

There are 7 types of residential circuits.

<u>Explanation:</u>

Resendential Circuits means circuits used while wiring residential buildings. There are 6 different types of resedential wirings. Outlet Circuit, Lighting Circuit, Room Circuit, Special Circuit, 240 Volt Circuit, GFCI Circuit, and AFCI Circuit.

All the basic circuits of resedential building are connected with an outlet circuit, and this type of circuit have 15 - 20 amps of pole breaker. Lightening Circuit is only for the wiring of lights in the complete resedential building, so that if anything goes wrong in lights, we could inspect that much only.

Sometimes, even there is a separate circuit for Rooms, and in resedential building, each and every room have different circuit. There are many appliances which require very high wattage like furnaces, or refrigerator.

For them, special circuit is down and pole breaker is generally upto 30 apms. More heavy duty appliances are wired by 240 Volt Circuit, and GFCI and AFCI Circuits are for safety measures and to cutoff all the circuits if anything goes wrong.

lakkis [162]3 years ago
4 0
I’m pretty sure it’s c. 5
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2 years ago
The nuclear reactions resulting from thermal neutron absorption in boron and cadmium are 10B5 + 1 n0 ï  7Li3 + 4He2 113Cd48 + 1
kirill115 [55]

Solution :

The nuclear reaction for boron is given as :

$^{10}\textrm{B}_5 + ^{1}\textrm{n}_0 \rightarrow ^{7}\textrm{Li}_3 + ^{4}\textrm{He}_2$

And the reaction for Cadmium is :

$^{113}\textrm{Cd}_48 + ^{1}\textrm{n}_0 \rightarrow ^{114}\textrm{Cd}_48 + \gamma [5 \ \textrm{MeV}]$

We know that it is easier that to shield or stop an alpha particle (i.e. He nucli) as they can be stopped or obstructed by only a few centimetres of the material. However, the gamma rays ( γ ) can penetrate through the material to a greater distance. Therefore, we can choose the first one.

6 0
2 years ago
Show that for a linearly separable dataset, the maximum likelihood solution for the logisitic regression model is obtained by fi
KATRIN_1 [288]

Answer:

Answer for the question:

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is explained in the attachment.

Explanation:

8 0
3 years ago
Which option should the engineers focus on as they develop the train in the following scenario?
pav-90 [236]

Answer:

  Engineers can design a train with a regenerative braking system

Explanation:

Assuming the point of the question is that the engineers want to focus on using energy efficiently when starting and stopping, they would likely want to consider a regenerative braking system. Such a system can store energy during braking so that it can be used during starting, reducing the amount of energy that must be supplied by an outside power source.

5 0
3 years ago
Steam at a pressure of 100 bar and temperature of 600 °C enters an adiabatic nozzle with a velocity of 35 m/s. It leaves the noz
butalik [34]

Answer:

Exit velocity V_2=1472.2 m/s.

Explanation:

Given:

At inlet:

P_1=100 bar,T_=600°C,V_1=35m/s

Properties of steam at 100 bar and 600°C

        h_1=3624.7\frac{KJ}{Kg}

At exit:Lets take exit velocity V_2

We know that if we know only one property inside the dome  then we will find the other property by using steam property table.

Given that dryness or quality of steam at the exit of nozzle  is 0.85 and pressure P=80 bar.So from steam table we can find the other properties.

Properties of saturated steam at 80 bar

   h_f= 1316.61\frac{KJ}{Kg} ,h_g= 2757.8\frac{KJ}{Kg}

So the enthalpy of steam at the exit of turbine  

h_2=h_f+x(h_g-h_f)\frac{KJ}{Kg}

h_2=1316.61+0.85(2757.8-1316.61)\frac{KJ}{Kg}

 h_2=2541.62\frac{KJ}{Kg}

Now from first law for open system

h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w

In the case of adiabatic nozzle Q=0,W=0

3624.7+\dfrac{35^2}{2000}+0=2541.62+\dfrac{(V_2)^2}{2000}+0

V_2=1472.2 m/s

So Exit velocity V_2=1472.2 m/s.

4 0
3 years ago
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