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PilotLPTM [1.2K]
3 years ago
15

Your family just had a nee refrigerator delivered. The delivery man has left and you realize that the refrigerator is not quite

in the right position, so you plan to move ut several netimeters. If the refrigerator has a nass of 88kg, the coefficient of kinetic friction between the bottom of the refrigerator and the floor is 0.13, and the static coefficient of friction between these same surfaces is 0.21. How hard do you have to push horizontally to get the refrigerator to start moving?
Physics
1 answer:
harkovskaia [24]3 years ago
6 0

To get it to start moving, he have to exert a force equal to its maximum force of static friction.

F= fs,max = Ms m g= (0.21) * (180) * (9.8) = 370 N

Let me know if im wrong but if not brainliest user for helping or best answer

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A car has an acceleration of 1.5 m/s2. A net force of 2100 N is acting on the car. What is the mass of the car?
gulaghasi [49]

Answer:

Given

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8 0
3 years ago
Tap on the photo. For each diagram, explain why the light behaves in the way that it does.
dem82 [27]

Answer:

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n_1 sin \theta_1 = n_2 sin \theta_2

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\theta_1, \theta_2 are the angle that the incident ray and the refracted ray makes with the normal to the interface

In diagram, 1, the ray of light arrives perpendicularly to the interface, so it is refracted through the medium but it doesn't change its direction (only its speed).

In diagram 3, the ray of light is refracted twice: at the 1st interface and at the 2nd interface. In the 1st case, it goes from a medium with lower refractive index to a medium with higher refractive index (n_1), this means that \theta_2, so the ray bends towards the normal. Vice-versa, in the 2nd case the ray goes from a medium with higher refractive index to a medium with lower refractive index (n_1>n_2), so it bends away from the normal (\theta_2>\theta_1).

In diagram 4, the ray of light is also refracted twice. The ray of light here acts exactly the same as in diagram 3, h

However, this time the 2nd interface is the opposite direction with respect to diagram 3, so in this case the ray of light at the 2nd interface bends in the opposite direction (still away from the normal).

Diagram 2 instead is an example of reflection, that occurs when a ray of light bounces off the interface between the two mediums, withouth entering the 2nd medium.

According to the law of reflection:

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- The angle of incidence is equal to the angle of reflection (both are measured relative to the normal to the boundary)

Therefore in this diagram, the ray of light hits the boundary at approx. 45 degrees from the normal, and then it is reflected back approximately at 45 degrees on the other side with respect to the normal.

3 0
4 years ago
Consider the electric field lines drawn below for a configuration of two charges. Several locations are labeled on the diagram.
geniusboy [140]

Answer:

The magnitude or strength of an electric field in the space surrounding a source charge is related directly to the quantity of charge on the source charge and inversely to the distance from the source charge. The direction of the electric field is always directed in the direction that a positive test charge would be pushed or pulled if placed in the space surrounding the source charge.

Explanation:

I really hope this helps you!

6 0
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