When practicing an oral presentation what can you do to prepare for the presentation
1 answer:
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Answer:
The volume of water that was in the kettle is 1170
Explanation:
Given:
Power, P = 2.0 kW = 2000 W, Mass of stainless steel, = 710 g = 0.71 kg at temperature of
Part A:
If it takes time, t = 3.5 minutes to reach boiling point of water , then from conservation of energy,
Total energy supplied by the burner = Total heat gained by the water and the stainless steel to rise from to
i.e. Pt = (100 - 20 ) +
(100 - 20 )
=
= 1.17 kg
where = 4200 J/Kgk (specific heat capacity of water),
= 450 J/Kgk (specific heat capacity of steel)
But volume of water in the the kettle, v =
∴ v = 1170