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2 years ago

5

Hey I need help w/ this pic below ASAP!!! Pls will mark brainliest:) Not joking lol

2 answers:

Ainat [17]2 years ago

8 0

There’s no picture…

Arturiano [62]2 years ago

4 0

Where is the picture

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Which of the following activities could lead to injuries?

Ipatiy [6.2K]

Answer:

Fighting

Explanation:

Fighting with someone like punch for punch can make the person bleed which an injury to the guy who you fought with and you can be arrested if the parents file a complain at the police station

6 0

3 years ago

Read 2 more answers

[High Dive) above a pool of water. According to the announcer, the divers enter the water at a speed of 56 mi/h (25 m/s). (Air r

blsea [12.9K]

Answer:

(a) The announcer's claim is incorrect because the divers enter at a speed of 20.4 and not 25 m/s as announced

(b) it’s possible for a diver to enter the water with the velocity of 25 m/s if he has initial velocity of 14.4 m/s. The upward initial velocity can’t be physically attained

Explanation:

(a)

To find the final velocity $V_{f}$ for an object traveling distance h taking the initial vertical component of velocity as $V_{i}$ the kinematics equation is written as

$V_{f}^{2}=V_{i}^{2}+2ah$ where a is acceleration

Substituting g for a where g is gravitational force value taken as 9.81

$V_{f}^{2}=V_{i}^{2}+2gh$

Since the initial velocity is zero, we can solve for final velocity by substituting figures, note that 70 ft is 21.3 m for h

$V_{f}=\sqrt {(2gh)}= V_{f}=\sqrt {(2*9.81*21.3)}$ = 20.44275

Therefore, the divers enter with a speed of 20.4 m/s

The announcer's claim is incorrect because the divers enter at a speed of 20.4 and not 25 m/s as announced

(b)

The divers can enter water with a velocity of 25 m/s only if they have some initial velocity. Using the kinematic equation

$V_{f}^{2}=V_{i}^{2}+2gh$

Since we have final velocity of 25 m/s

$V_{i}^{2}=2gh-V_{f}^{2}$

$V_{i}=\sqrt{(V_{f}^{2}-2gh)}$

$V_{i}=\sqrt{(25^{2}-2*9.81*21.3)}$ = 14.390761 m/s

Therefore, it’s possible for a diver to enter the water with the velocity of 25 m/5 if he has initial velocity of 14.4 m/s

In conclusion, the upward initial velocity can’t be physically attained

3 0

3 years ago

Boiling point (when a liquid change to gas) is a physical property of matter. I want to determine if the amount of water will ha

Tanzania [10]

Answer:

E

Explanation:

They will boil at the same temperature.

And remember Christ loves you and

Jesus is coming back soon get right with Christ please

4 0

3 years ago

what consistent physiological pattern are more common in women's teeth? A. Women's canines are generally sharper. B. Women have

irakobra [83]

Answer:

B

Explanation:

B. Women have straighter teeth.

5 0

3 years ago

A track is traveling a. a speed of 25.0 m/s along a level road. A crate is resting on the bed of the truck, and the coefficient

Mice21 [21]

To solve this problem it is necessary to apply the concepts related to

conservation of energy, for this case manifested through work and kinetic energy.

$W = \Delta KE$

$W = F*d$

Where,

F= Force (Frictional at this case $F_r = \mu N$ )

d= Distance

$\Delta KE = \frac{1}{2} mv^2$

Where,

m = mass

v = velocity

Equation both terms,

$F*d = \frac{1}{2}mv^2$

$\mu mg *d = \frac{1}{2}mv^2$

$\mu g * d = \frac{1}{2}v^2$

$d = \frac{1}{2} \frac{v^2}{\mu g}$

Replacing with our values we have that

$d = \frac{1}{2} \frac{25^2}{0.65*9.8}$

$d = 49.05m$

Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m

6 0

2 years ago