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V125BC [204]
3 years ago
14

Chlorine oxide (ClO), which plays an important role in the depletion of ozone, decays rapidly according to the equation 2ClO(g)

→ Cl2(g) + O2(g) From the following data, determine the reaction order and calculate the rate constant of the reaction. Time (s) [ClO] (M) 4.26 × 10−3 7.73 × 10−6 4.88 × 10−3 6.27 × 10−6 5.50 × 10−3 5.28 × 10−6 6.12 × 10−3 4.56 × 10−6 6.74 × 10−3 4.01 × 10−6
Chemistry
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

It is a zero order reaction and k=0.005M/s

Explanation:

Once you plot the graph, you can see it is a linear equation which decays. This is common to zero order reaction which are given by the following equation: C=Co-kt. The equation given by the graph is C=1x10-5 - 0.0015t. Therefore, the slope = -K

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The pOH of a solution is 10.75. What is the concentration of OH– ions in the solution?. A. –1.031 M. B. 1.778 x 10–11 M. C. 5.62
zloy xaker [14]
We are given the pOH of the solution of 10.75. pOH is the property of the solution that is related to the OH ion concentration of the solution. THe formula to be followed is pOH = -log (OH); OH- = 10^-pOH. In this case, OH-  = 10^-10.75 equal to B. 1.778 x 10^-11 M
5 0
2 years ago
B. Which of the following compounds can
Tamiku [17]

Answer:

The correct answer is:

d. Na2S, NaF

4 0
2 years ago
Read 2 more answers
What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 54?
Anika [276]

Answer:

1. Caffeine, C₈H₁₀N₄O₂

Amount = 1.00/194 = 0.00515 moles

2. Ethanol, C₂H₅OH

Amount = 0.0217 moles

3. Dry Ice, CO₂

amount = 0.0227 moles

<em>Note: The question is incomplete. The compound are as follows:</em>

<em> 1. Caffeine, C₈H₁₀N₄O₂;</em>

<em>2. Ethanol, C₂H₅OH;</em>

<em>3. Dry Ice, CO₂</em>

Explanation:

Amount (moles) = mass in grams /molar mass in grams per mole

1. Caffeine, C₈H₁₀N₄O₂

molar mass of caffeine = 194 g/mol

Amount = 1.00 g/194 g/mol = 0.00515 moles

2. Ethanol, C₂H₅OH

molar mass of ethanol = 46 g/mol

Amount = 1.00 g/46 g/mol = 0.0217 moles

3. Dry Ice, CO₂

molar mass of dry ice = 44 g/mol

amount = 1.00 g/44 g/mol = 0.0227 moles

5 0
2 years ago
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0
2 years ago
Give six examples of complex compounds.
ra1l [238]

Answer:

Examples of complex compound include potassium ferrocyanide K4[Fe(CN)6] and potassium ferricyanide K3[Fe(CN)6]. Other examples include pentaamine chloro cobalt(III) chloride [Co(NH)5Cl]Cl2 and dichlorobis platinum(IV) nitrate [Pt(en)2Cl2](NO3)2.

3 0
3 years ago
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