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e-lub [12.9K]
2 years ago
8

If the number of unemployed workers is 19 million, the number in the working-age population is 500 million, and the unemployment

rate is 4%, what is the labor force participation rate
Physics
1 answer:
Darina [25.2K]2 years ago
6 0

Answer:

The percentage of the population that is actively participating in the labor market, whether working or looking for a job, is 95% of the total working age population.

Explanation:

If the number of unemployed in a country is 19 million people, and that number represents an unemployment rate of 4%, to know the total number of economically active people in the country we must perform the following calculation:

(19,000,000 / 4) x 100 = X

475,000,000 = economically active population

However, the country has a working-age population of 500 million people, of which only 475 are actively participating in the labor market. To know the percentage that these 475 million people represent, we must perform the following cross multiplication:

500 = 100

475 = X

(475 x 100) / 500 = X

95 = X

The percentage of the population that is actively participating in the labor market, whether working or looking for a job, is 95% of the total working age population.

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Answer: minimum speed of launch must be 7.45m/s

Explanation:

Given the following:

Height or distance (s) = 2.83m

The final velocity(Vf) at maximum height = 0

Upward motion, acceleration due to gravity(g) us negative = -9.8m/s^2

From the 3rd equation of motion:

V^2 = u^2 - 2gs

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u = initial velocity

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u = √Vf^2 - 2gs

u = √0^2 - 2(-9.8)(2.83)

u = √0 + 55.468

u = √55.468

u = 7.4476 m/s

u = 7.45m/s

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3 years ago
Which is the best definition to describe a transfer of energy?
MissTica

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a

Explanation:

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2 years ago
Anyone.... help with this two questions...​
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A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the  force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

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3 years ago
According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s
Mademuasel [1]

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

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\tau_{net} = 0

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\frac{dL}{dt}= 0

now we also know that

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so rate of change in area is given as

\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}

so we will have

\frac{dA}{dt} = \frac{1}{2}r^2\omega

\frac{dA}{dt} = \frac{L}{2m}

since angular momentum and mass is constant here so

all planets sweeps out equal areas in equal times.

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3 years ago
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