I did the math on Photomath so here is what I got.
Can you use Pythagorean Theorem to find the missing side? Why or why not?
1 answer:
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For graphing make sure to shade the right portion and to make the line dotted like (— — — —)
the red is y>8x-4, the blue is y>-1/2x+1/2
2x-.25y < 1 is equal to 2x-1/4y < 1
multiply each side by 4:
8x-y < 4
add y to each side:
8x < 4+y
subtract 4 from each side:
8x-4 < y
rewrite:
y > 8x-4
4x+8y > 4
divide both sides by 8:
1/2x+y > 1/2
subtract -1/2x from each side:
y > -1/2x + 1/2
the red is y>8x-4, the blue is y>-1/2x+1/2
2x-.25y < 1 is equal to 2x-1/4y < 1
multiply each side by 4:
8x-y < 4
add y to each side:
8x < 4+y
subtract 4 from each side:
8x-4 < y
rewrite:
y > 8x-4
4x+8y > 4
divide both sides by 8:
1/2x+y > 1/2
subtract -1/2x from each side:
y > -1/2x + 1/2
Answer:
c
Step-by-step explanation:
Answer:
Figure show demonstration of and
Step-by-step explanation:
Let chosen fraction be
Now we multiply fraction with
Result will be
=
=
Figure show demonstration of and
