Answer:
Hey, I don't know but try 10+ (h) + 5 ), 79
__MgF2 + __Li2CO3 + __ 2LiF
C9H20 + 14O2 --> 9CO2 + 10H2O
22.4L
of any gas contains 1 mol of that gas.
50.75g/10L*22.4L/1 mol= 113.68g/mol- this is the mole weight of your gas
1 mol/113.68g*129.3g=1.137403 mol
Set up a ratio
1.137403mol/x L=1 mol/22.4 L
X=25.477827L, or with sig figs, x=25.5L
