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sleet_krkn [62]
3 years ago
5

Which of the following statements provides the BEST explanation for the many chemical similarities between two elements in a Mai

n Group? (Note: only ONE answer here.!) (a) They have similar atomic mass values. (b) Both have the same number of valence electrons. (c) They have the same number of protons. (d) They are in the same period.
Chemistry
1 answer:
rjkz [21]3 years ago
7 0

Answer:

(b) Both have the same number of valence electrons.  

Step-by-step explanation:

We find the most striking chemical similarities between two Main Group elements when they are in the same Group of the Periodic Table.

Elements in the same Group have the same number of valence electrons.

(a) is <em>wrong</em>, because elements in the same group have <em>different masses</em>.

(c) is <em>wrong,</em> because atoms with the same number of protons belong to the s<em>ame element</em>.

(d) is wrong, because elements in the same Group must be in . <em>different Periods.</em>

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If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
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Answer:30 L

Explanation:

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Since the pressure is constant and the question is asking about temperature and volume, i.e,

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6 0
3 years ago
What could we use to measure the energy of particles when we are unable to see them
iVinArrow [24]

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Using the Law of Conservation of Matter, determine the number of grams of iron sulfide (FeS) that will be produced in this react
vazorg [7]
The Law of Conservation of Mass states that the mass of reactants entering a reaction must be equal to the mass of the products exiting it. In this case, we only have 2 reactants, Fe and S, and we only have 1 product, FeS. Therefore we expect the total mass of the Fe and S reactants to equal the mass of FeS. This gives us 112 g + 64 g = 176 g of FeS, which is choice D.

4 0
3 years ago
Read 2 more answers
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
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