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Step2247 [10]
3 years ago
7

A boy and his skateboard have a combined mass of 65 kg. What is the speed of the boy and skateboard if they have a momentum of 2

75 kg • ? 0 m/s 0.24 m/s 4.2 m/s 8.5 m/s
Physics
2 answers:
dezoksy [38]3 years ago
8 0

Answer : Speed is 4.2 m/s

Explanation :

The combined mass of the boy and the skateboard is 65 kg

The momentum of the boy and the skateboard is 275 kg m/s

The momentum is given by:

p = m v

where m is the combined mass of boy and the skateboard.

v is the speed of both boy and the skateboard.

v=\dfrac{p}{m}

v=\dfrac{275\ kg\ m/s}{65\ kg}

v=4.23\ m/s

The speed of the boy and the skateboard is 4.2 m/s

So, the correct option is (C).

Hence, this is the required solution.

Yanka [14]3 years ago
3 0
4.2m/s. Momentum=mass x velocity so 275/65=velocity=4.23
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Taking into account the definition of velocity, Clara's average velocity is 0.5 m/s.

<h3>Definition of velocity</h3>

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction. So it is considered a vector magnitude.

In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction, and can be calculated using the expression:

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<h3>Average velocity of Clara</h3>

Clara rushes 30 m to a truck then turns and walks back. Total travel is 120s. Then, you know:

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Replacing in the definition of velocity:

velocity= 60 m÷ 120 s

Solving:

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Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential
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Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

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When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

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dividing through by 2.0 V, we have

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taking the reciprocal, we have

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From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

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So, R₂ = V₂/I₂

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= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0
3 years ago
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