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noname [10]
2 years ago
10

An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the

Physics
1 answer:
Ann [662]2 years ago
7 0

Answer:

b

Explanation:

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(c) If η = 60% and TC = 40°F, what is TH, in °F?
arlik [135]
2b2t hope that helps
5 0
2 years ago
Two trains are blowing their whistles. The first train is stationary, and the
Liono4ka [1.6K]

Answer:

A I think

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3 0
3 years ago
A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the
sp2606 [1]
From the question,
u = 0m {s}^{ - 1}
v = 6m {s}^{ - 1}

t = 3s
F=12N



Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.

Ft =m(v-u)


12(3.0)=m(6.0- \: 0)
This implies that

36.0 = 6m
m =  \frac{36.0}{6.0}
\therefore \: m = 6.0kg


You can also use the equation of linear motion,
v = u + at
6 = 0 + a(3)
6 = 3a
a =  \frac{6}{3}

a = 2 {ms}^{ - 2}
But
F=ma
12 = m(2)
12 = 2m
\frac{12}{2}  = m
\therefore \: m = 6kg
4 0
3 years ago
Of the three sciences, physics, chemistry, and biology, the most complex is
Agata [3.3K]

Answer:

I would probably say C to be completely honest

Explanation:

If you agree make sure to give me a like

6 0
2 years ago
How much time will it take to do 33j of work with 11 w of power
Yuri [45]

Time required : 3 s

<h3>Further explanation </h3>

Power is the work done/second.

\tt P=\dfrac{W}{t}\\\\P=power,j/s,watt\\\\W=work, J\\\\t=times=s

 

To do 33 J of work with 11 W of power

P = 11 W

W = 33 J

\tt t=\dfrac{W}{P}\\\\t=\dfrac{33}{11}\\\\t=\boxed{\bold{3~s}}

8 0
3 years ago
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