Answer:
Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.
Explanation:
We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.
We will use Kepler's Law to solve our given problem.
Upon substituting our given values, we will get:
Taking square root of both sides, we will get:
This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.
So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.
Answer:
The height from which the ball was thrown is 18.82 m
Explanation:
Given;
horizontal velocity of the ball, vi = 27.0 m/s
horizontal distance of the ball, d = 53.0 m
Apply kinematic equation, to determine the time taken for the ball to make a horizontal distance of 53.0 m.
d = vt
t = d/v
t = 53/27
t = 1.96 seconds
This time is equal to the time the ball spent in air before hitting the ground.
The vertical distance at this time, is the height from which the ball was thrown, and it is calculated as;
h = vt + ¹/₂gt²
v is vertical velocity, = 0
g is acceleration due to gravity
h = ¹/₂ x 9.8 x (1.96)²
h = 18.82 m
Therefore, the height from which the ball was thrown is 18.82 m
Answer:
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Explanation:
the body is said to be in equilibrium if it is resting or moving with uniform velocity.
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