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Vanyuwa [196]
3 years ago
5

What is the centripetal force of an object undergoing uniform circular motion when its radius is doubled and its speed remains c

onstant?
A.
the same as before
B.
twice as great as before
C.
half as great as before
D.
four times as great as before
Physics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

C

Explanation:

Now the centripetal force is that force that keeps the object on course along the circle;

This is expressed mathematically as ;

F = mv^2/ r

Where F - centripetal force

m- mass of the object

v- velocity of the object

r- raduis

Note from the expression as r increases F decreases so if v and the mass is constant if r doubles F will reduce by half.

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An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force
Delicious77 [7]

Answer:

The gravitational force on the elevator = 4500N

Explanation:

The given parameters are;

The force applied by the elevator, F  = 4500 N

The acceleration of the elevator = Not accelerating

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;

F = W + Mass of elevator × Acceleration of elevator

∴ F = W + Mass of elevator × 0 = W

F = 4500 N = W

The net force on the elevator is F - W = 0

The gravitational force on the elevator = W = 4500N.

3 0
3 years ago
A beryllium-9 ion has a positive charge that is double the charge of a proton, and a mass of 1.50 ✕ 10−26 kg. At a particular in
seropon [69]

Answer:

Magnetic force, F = 3.52\times 10^{-13}\ N

Explanation:

Given that,

A beryllium-9 ion has a positive charge that is double the charge of a proton, q=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C

Speed of the ion in the magnetic field, v=5\times 10^6\ m/s

Its velocity makes an angle of 61° with the direction of the magnetic field at the ion's location.

The magnitude of the field is 0.220 T.

We need to find the magnitude of the magnetic force on the ion. It is given by :

F=qvB\\\\F=3.2\times 10^{-19}\times 5\times 10^6\times 0.22\\\\F=3.52\times 10^{-13}\ N

So, the magnitude of magnetic force on the ion is 3.52\times 10^{-13}\ N.

3 0
3 years ago
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Answer:

150.6 km

Explanation:

One mile is about 1.61 km so multiply 93.6 by 1.6 which gives you above 150.6

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Blizzard [7]

Answer:

Current- the flow of free charges, such as electrons and ions

Drift velocity- the average speed at which these charges move

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Brrunno [24]

Answer:D

Explanation:

It was right o khan academy

6 0
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