<u>Answer:</u>
<em>When red light enters the lens its wavelength decreases but its frequency remains the same.
</em>
<u>Explanation:</u>
Lens is made of glass which is a <em>denser medium</em> when compared with air. Thus light will undergo refraction and bend toward the normal. On entering a denser medium from rarer medium the speed of light decreases.
<em>Speed, frequency and wavelength of an electromagnetic wave</em> are related according to the equation.
<em> v=ϑλ
</em>
Where is <em>v is the frequency, λ is the wavelength and v is the speed of the em wave.
</em>
On entering the lens the wavelength of the red light as well as speed decreases but the<em> frequency remains the same.
</em>
Answer:
a) v² = G M R³, b) T = 2π /
, c) 
Explanation:
a) The kinetic energy is
K = ½ m v²
to find the velocity let's use Newton's second law
F = m a
acceleration is centripetal
a = v² / R
force is the universal force of attraction
F = G m M / r²
we substitute
G m M R² = m v² R
v² = G M R³
the kinetic energy is
K = ½ m G M R³
b) angular and linear velocity are related
v = w R
w = v / R
w =
w =
the angular velocity is related to the period
w = 2π / T
T = 2π / w
we substitute
T = 2π /
c) the angular moeomto is
L = m v r
L = m RA G M R³ R
L = 
The expression for the frictional force between the sled and the ground is:

where

is the coefficient of friction, m is the mass of the object and

is the gravitational acceleration.
The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
Answer:
Explanation:
Mass of ice m = 500g = .5 kg
Heat required to raise the temperature of ice by 10 degree
= mass of ice x specific heat of ice x change in temperature
= .5 x 2093 x 10 J
10465 J
Heat required to melt the ice
= mass of ice x latent heat
0.5 x 334 x 10³ J
167000 J
Heat required to raise its temperature to 18 degree
= mass x specific heat of water x rise in temperature
= .5 x 4182 x 18
=37638 J
Total heat
=10465 +167000+ 37638
=215103 J