1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gregori [183]
3 years ago
7

How does information appear to be science?

Chemistry
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

The information become scientific when it was proved by different experiments and first it become theory then law and we study these information in books

Explanation:

You might be interested in
What are the extremely small particles that all elements are composed of?
muminat
Atoms is the correct answer
7 0
3 years ago
Read 2 more answers
Diet soda has a lower density than bottled water True False
Rus_ich [418]
The answer to the question is false 
3 0
3 years ago
Read 2 more answers
Which of these statements is not true about chemical reaction rates?
xeze [42]
Temperature can change a reaction rate because adding or taking away heat means energy is being added or taken away. When energy is added, the particles speed up, so there is a greater chance of the reactants colliding to form the products, which increases the reaction rate. When energy is taken away, the particles more slower, so they don't collide as easily, which slows down the reaction rate.

Therefore, the answer is D.
3 0
3 years ago
Read 2 more answers
Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0
3 years ago
What information does a solubility table give?
guajiro [1.7K]

Answer:

Option D - It tells which compounds will dissolve in water.

Explanation:

It is used to predict whether or not a given ionic compound is soluble.

4 0
2 years ago
Read 2 more answers
Other questions:
  • Why could the mass of argon be greater than the mass of potassium even though it has a lower atomic number?
    14·1 answer
  • Explain why aluminum is a substance
    11·2 answers
  • During chemical reactions, energy is
    9·2 answers
  • A sample of an unknown substance has a mass of 0.465 kg. If 3,000.0 J of heat is required to heat the substance from 50.0°C to 1
    12·2 answers
  • What is accretion?????
    9·2 answers
  • What are all the ways that a substance can change state?
    12·2 answers
  • H2 + O2 -&gt; 2H2O <br> balanced or unbalanced pls help
    13·1 answer
  • For each pair circle the neutral element with the largest atomic radius K or Cs ,Ti or As ,Br or F
    5·1 answer
  • In the following reaction, how many liters of oxygen will react with 270 liters of ethene (C2H4) at STP?
    7·1 answer
  • PLEASE HELP ME!!!!! I NEED REAL HELP PLEASE I KEEP GETTING NON REAL ANSWERS!!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!