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mote1985 [20]
3 years ago
10

Alpha helices are a type of secondary structure in proteins. What is the length of a 33.0 kDa single‑stranded α‑helical protein

segment? Assume a mean residue mass of 110 Da . length: Å
Chemistry
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

450 Å

Explanation:

The amino acids in an α-helix are arranged in a right-handed helical structure where each amino acid residue corresponds to a 100° turn in the helix, and a translation of 1.5 Å (0.15 nm) along the helical axis

Mass of protein= 33.0 kDa

33.0 kDa ×(1000Da/kDa) × ( 1 residue/ 110 Da)

=33.0 ×1000 × 0.0091

= 300 residues

300 residues × (1.5Å /residue)

=450 Å

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Zinc and sulfuric acid solution produce zinc sulfate solution and hydrogen balanced chemical equation
IRISSAK [1]

Answer:

Zn + H2SO4 → ZnSO4 + H. 2

Explanation:

8 0
3 years ago
Damian mixed two samples together: a
lesantik [10]

Answer:C

Explanation:

3 0
2 years ago
Can someone help me fill out the chart and explain what i should do, please?
Alina [70]

To determine the electronegativity for each bond you need to calculate the difference of electronegativity of the atoms forming the bond.  

If the difference is equal or greater than 1.7 you have an ionic bond.

If the difference is between 0.4 and 1.6  you have a polar covalent bond.

If the difference is between 0 and less than 0.4 you have a nonpolar covalent bond.  

1) In NH₃ there is a nitrogen - hydrogen bond.  

electronegativity of nitrogen - electronegativity of hydrogen =

3 - 2.2 = 0.8 → polar covalent bond

2) In N₂ there is a nitrogen-nitrogen bond.

electronegativity of nitrogen - electronegativity of nitrogen =

3 - 3 = 0 → nonpolar covalent bond

3) In H₂O there is an oxygen - hydrogen bond.  

electronegativity of oxygen - electronegativity of hydrogen =

3.5 - 2.2 = 1.3 → polar covalent bond

4) In PCl₃ there is a chlorine - phosphorus bond.  

electronegativity of chlorine - electronegativity of phosphorus = 3 - 2.1 = 0.9 → polar covalent bond

4) In HBr there is a bromine - hydrogen bond.  

electronegativity of bromine - electronegativity of hydrogen = 2.8 - 2.2 = 0.6 → polar covalent bond

5) In MgCl₂ there is a chlorine - magnesium bond.  

electronegativity of chlorine - electronegativity of magnesium = 3 - 1.2 = 1.8 → ionic bond

6) In F₂ there is a fluorine - fluorine  bond.  

electronegativity of fluorine - electronegativity of fluorine =

4 - 4 = 0 → nonpolar covalent bond

7) In CO₂ there is an oxygen - carbon bond.  

electronegativity of oxygen- electronegativity of carbon =

3.5 - 2.5 = 1 → polar covalent bond

8) In LiCl there is a chlorine - lithium bond.  

electronegativity of chlorine - electronegativity of lithium =

3 - 1 = 2 → ionic bond

9) In Na₂O there is an oxygen - sodium bond.

electronegativity of oxygen - electronegativity of sodium =

3.5 - 0.9 = 2.6 → ionic bond

10)  In CCl₄ there is a chlorine - carbon bond.  

electronegativity of chlorine - electronegativity of carbon =

3 - 2.5 = 0.5 → polar covalent bond

5 0
3 years ago
A 0.187 M weak acid solution has a pH of 3.99. Find Ka for the acid. Express your answer using two significant figures.
Anna35 [415]

Answer:

5.56 × 10⁻⁸

Explanation:

Step 1: Given data

  • Concentration of the weak acid (Ca): 0.187 M
  • pH of the solution: 3.99

Step 2: Calculate the concentration of H⁺

We will use the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -3.99 = 1.02 × 10⁻⁴ M

Step 3: Calculate the acid dissociation constant (Ka)

We will use the following expression.

Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(1.02 \times 10^{-4})^{2} }{0.187} = 5.56 \times 10^{-8}

3 0
2 years ago
the reaction of aluminum with chlorine gas is shown 2Al + 3Cl2 -> 2AlCl3 based on this equation how many molecules of chlorin
Vanyuwa [196]

45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

The balanced equation for the reaction is given below:

2Al + 3Cl₂ —> 2AlCl₃

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

Therefore,

30 atoms of Al will require = \frac{30 * 3}{2}\\ = 45 molecules of Cl₂.

Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

Learn more: brainly.com/question/24918379

3 0
2 years ago
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