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Papessa [141]
3 years ago
11

A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.9-T magnetic field. The loop is rotated so that its p

lane is parallel to the field direction in 0.15 s.What is the average induced emf in the loop?
Physics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

0.3405V

Explanation:

#Given a magnetic field of 1.9T, diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:

\phi=B.(\pi r^2)cos 0\textdegree\\=1.9\pi\times 0.0925^2 \times cos 0\textdegree\\=5.107\times10^-^2 \ Tm^2

we can now calculate the induced emf, \frac{\phi}{\bigtriangleup t}:

\frac{\phi}{\bigtriangleup t}=\frac{5.107\times 10^-^2}{0.15}\\=3.405\times 10^-^1V

Hence, the induced emf of the loop is 0.3405V

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