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crimeas [40]
3 years ago
5

2 radioactive isotopes of oxygen?

Chemistry
1 answer:
Lemur [1.5K]3 years ago
8 0
<span>Oxygen-15 is an isotope of oxygen, frequently used in positron emission tomography, or PET imaging. It has 8 protons, 7 neutrons, and 8 electrons. The total atomic mass is 15.0030654 amu. It has a half-life of 122.24 seconds.</span>
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A spring scale is MOST useful in measuring _____.
lesantik [10]
A spring scale measures weight. some even use them to measure the weight of fish
8 0
3 years ago
Read 2 more answers
7. A cyclist starting from rest accelerates at a rate of 6 m/s until she reaches 30 m/s. How long
Hunter-Best [27]

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

a=\frac{v-u}{t}

thus,

t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds

4 0
3 years ago
There are 3.0 g of NO and 3.0 g of CO reacting. what is the limiting reactant ?
xxTIMURxx [149]

Answer:

NO will be the limiting reagent.

Explanation:

The balanced equation is:

2 NO + 2 CO → N₂ + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • NO: 2 moles
  • CO: 2 moles
  • N₂: 1 mole
  • CO₂: 2 moles

Being the molar mass of each compound:

  • NO: 30 g/mole
  • CO: 28 g/mole
  • N₂: 28 g/mole
  • CO₂: 44 g/mole

Then by stoichiometry the following quantities of mass participate in each reaction:

  • NO: 2 moles* 30 g/mole= 60 g
  • CO: 2 moles* 28 g/mole= 56 g
  • N₂: 1 mole* 28 g/mole= 28 g
  • CO₂: 2 moles* 44 g/mole= 88 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?

mass of NO=\frac{3 grams of CO*60 grams of NO}{56 grams of CO}

mass of NO= 3.21 grams

But 3.21 grams of NO are not available, 3 grams are available. Since you have less moles than you need to react with 3 grams of CO, <u><em>NO will be the limiting reagent. </em></u>

<u><em></em></u>

4 0
3 years ago
Which of the following best describe arrangement of particles in a gas?
Maslowich

Answer:

last one

Explanation:

makes the most sense

8 0
3 years ago
Production of Jam from Crushed Fruit in Two Stages. In a process producing jam (C1), crushed fruit containing 14 wt % soluble so
Andrej [43]

Answer:

The total kg from the mixer: m=2222.5 kg

Evaporated water: m_{water ev.}=791.1 kg

Jam produced: m_{jam}=1431.4 kg

Explanation:

Step by step:

1) Kg of mixture from the mixer

It says that crushed fruit is added to the mixer with the sugar and pectin.

The fruit added is 1000 kg

The sugar added is 1.22 kg sugar/1 kg crushed fruit:

m_{sugar}=1000 kg fruit * \frac{1.22 kg sugar}{1 kg fruit}=1220 kg sugar

The pectin added is 0.0025 kg pectin/1 kg crushed fruit:

m_{pectin}=1000 kg fruit * \frac{0.0025 kg pectin}{1 kg fruit}=2.5 kg pectin

The total kg from the mixer:

m=1000 kg fruit + 2.5 kg pectin + 1220 kg sugar=2222.5 kg

2) Evaporated water

To calculate the evaporated water it's important to have in mind that the mix goes from a concentration of 14 wt% to 67 wt%. This difference is because of the evaporated water. So:

Initial: 1000 kg of fruit with 14 wt% of solids

m_{solids}=1000 kg *0.14=140 kg

<em>This amount of solids is constant </em>

Final: The mass of solids is the same but now it represents the 67 wt%

m_{final}=140 kg *\frac{100}{67}=208.9 kg

and

m_{water ev.}=1000kg-m_{final}

m_{water ev.}=1000kg-208.9kg=791.1 kg

3) Jam produced

m_{jam}=m_{final}+m_{pectin}+m_{sugar}=208.9 kg + 1220 kg + 2.5 kg

m_{jam}=1431.4 kg

6 0
3 years ago
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