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Vladimir79 [104]
3 years ago
9

WILL MARK BRAINLIEST!!!40 POINTS!!! A. Is energy exchanged between your system (the device) and its surroundings? B. Is matter e

xchanged between your system (the device) and its surroundings? C. Is it an open, closed or isolated system? Explain. 2. What is the law of conservation of energy? 3. Describe two examples of how the law of conservation of energy is demonstrated in the device you created. 4. In the lesson a thermos is presented as an example of an isolated energy system. How could you change the thermos into an open energy system?

Physics
1 answer:
ValentinkaMS [17]3 years ago
5 0
The answer is A of the question
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Answer: Individuals with high self efficacy will participate readily and more frequently, will put more effort in and persist longer, enhancing performance in sport and exercise

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2 years ago
Two sources of light of wavelength 700 nm are 9 m away from a pinhole of diameter 1.2 mm. How far apart must the sources be for
Lelechka [254]

Answer:

The distance is  D  =  0.000712 \ m

Explanation:

From the question we are told that

    The wavelength of  the  light source is  \lambda  =  700 \ nm = 700 *10^{-9} \  m

     The distance from a pin hole is  x  =  9\ m

       The  diameter of the pin  hole is  d =  1.2 \ mm  =  0.0012 \ m

     

Generally the distance which the light source need to be in order for their diffraction patterns to be resolved by Rayleigh's criterion is

mathematically represented as

              D  =  \frac{1.22 \lambda }{d }

substituting values

             D  =  \frac{1.22 * 700 *10^{-9} }{ 0.0012 }

             D  =  0.000712 \ m

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3 years ago
What describes the movement of a fluid during convection?
damaskus [11]
Convection is the movement<span> of groups of molecules within </span>fluids<span> such as gases and liquids, including molten rock (rheid).</span>
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3 years ago
A particle moves along the curve below. y = sqrt(1 + x^3) As it reaches the point (2, 3), the y-coordinate is increasing at a ra
blagie [28]

Answer:7 cm/s

Explanation:

Given

Particle move along curve

y=\sqrt{1+x^3}

As it reaches the (2,3) its y coordinate is increasing at 14 cm/s

Differentiating y w.r.t time

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3x^2}{2\sqrt{1+x^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

Now at (2,3)

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3\cdot 2^2}{2\sqrt{1+2^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

14=\frac{3\times 4}{2\times \sqrt{9}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} x}{\mathrm{d} t}=7 cm/s

7 0
3 years ago
Dont use me for points please i need help, (circuits for physics)
zhannawk [14.2K]

Answer:

B, A, A, B

Explanation:

Just trust me on this one.

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2 years ago
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