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Eva8 [605]
3 years ago
11

If a ball has the weight of 3.76, how much work would it take to lift it 2 meters above the ground? (sorry if this question does

n't have all the components, im bad with physics)
Physics
1 answer:
Aloiza [94]3 years ago
7 0
We know, work done = Weight * Displacement 
w = 3.76 * 2
w = 7.52 J

In short, Your Answer would be: 7.52 Joules

Hope this helps!
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Find the right answer please
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Answer:

3.78

Explanation:

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Two magnets are arranged so that they pull together. Which conclusion can be reached? A.Two north poles are together. B. Two sou
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Answer is D. a north pole is near a south pole

Explanation:

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2 years ago
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Boron (B) has an atomic number of 5 and an atomic mass of 11. Boron has _____.
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Answer:

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Explanation:

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An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he
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Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

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6 0
3 years ago
A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i
Darya [45]

The position of the first ball is

y_1=h-\dfrac g2t^2

while the position of the second ball, thrown with initial velocity v, is

y_2=vt-\dfrac g2t^2

The time it takes for the first ball to reach the halfway point satisfies

\dfrac h2=h-\dfrac g2t^2

\implies\dfrac h2=\dfrac g2t^2

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\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2

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\implies v=\sqrt{hg}

8 0
3 years ago
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