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Vadim26 [7]
3 years ago
6

Write a function named is_float(s) that takes one argument that is a string. It returns True if string s represents a floating p

oint value and returns False otherwise. You are required to use try-except. The basic concept is to "try" to convert string s to a float and if it succeeds, return True, but if it fails (that is, an exception is raised), return False. Note that float() raises a ValueError exception.
Engineering
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

Explanation:

# Python Programme

#!/usr/bin/python

# Function definition is here

def is_float( str ):

try:

float(str)

return True

except ValueError:

return False

# Now you can call is_float function

print(is_float("3.45"))

print(is_float("3e4"))

print(is_float("abc"))

print(is_float("4"))

print(is_float(".5"))

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Soil engineering helps in analyzing the structure and composition of the soil of the proposed construction site, thus helping in deciding whether the soil of the proposed construction site or building is worth exploiting.

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2 years ago
Why dont some vehicles have power steering
daser333 [38]

Answer:

Because older cars didn't really have much power steering, and parking or even turning at low speeds could require a lot of strength to move the steering wheel on a big, heavy car. This moves the rack to the right or left, which turns the vehicle's wheels. Without power assist, you'd need grunt force to turn the pinion and move the rack.

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4 years ago
This test should be performed on all cord sets, receptacles that aren't part of a building or structure's permanent wiring, and
vova2212 [387]

Answer:

A continuity test

Explanation:

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8 0
3 years ago
How to make text take shape of object in affinity designer
Alina [70]

Answer:

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Explanation:

6 0
3 years ago
A piston–cylinder assembly contains propane, initially at 27°C, 1 bar, and a volume of 0.2 m3. The propane undergoes a process t
iren2701 [21]

Work done = -19.7 KJ

Heat transferred = 17.4 KJ

Explanation:

Given-

Temperature, T = 27°C

Volume, V = 0.2 m³

Pressure, P_{1}= 1 bar

v_{2} = 4 bar

pV¹°¹ = constant

From superheated propane table, at  P_{1}= 1 bar andT_{1}  = 27⁰C

v_{1} = 0.557 m³/kg

v_{2} = 473.73 KJ/kg

(a) Work = ?

We know,

V1¹°¹ = p2V2¹°¹

V2 = (\frac{P1}{P2})^\frac{1}{1.1} * V1  \\\\V2 = \frac{1}{4}^\frac{1}{1.1} * 0.557  \\\\V2 = 0.158 m^3/kg

At  = 4 bar and v = 0.158 m³/kg

u2 = 548.45K J/kg

To find work done in the process:

W = \frac{P2V2 - P1V1}{1-n} \\\\W = \frac{m(P2V2 - P1V1)}{1-n} \\\\W = \frac{v}{u} * \frac{P2V2 - P1V1}{1-n}\\  \\W = \frac{0.2}{0.5571} * \frac{4 X 0.158 - 1 X 0.577}{1-1.1} X 10^5 \frac{Pa}{Bar} \frac{1KJ}{10^3Nm} \\   \\W = -19.75KJ

(b) Heat transfer = ?

Q = m(u2 - u1) + W\\\\Q = \frac{0.2}{0.5571} * (548.45 - 473.73) + (-19.7)\\\\Q = 17.4KJ

8 0
4 years ago
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