Question

you travel 4.0km east, 4.0km north, then 5.0km at 53.1 degrees north of west in a total of 5 hours. What is the magnitude and direction of your average velocity

Answer 1

Answer:

Explanation:

We shall convert all the displacement in vector form .

i and j represents east and north respectively .

D₁ = 4 i

D₂ = 4 j

D₃ = - 5 cos 53.1 i + 5 sin 53.1 j

= -3i + 4 j

Total displacement = D₁ + D₂ + D₃

= 4i + 4 j - 3i + 4 j

= i + 8j

magnitude of displacement = √( 1² + 8² )

= 8.06 km

velocity = 8.06 / 5

= 1.61 km / h

Direction from x axis in anticlockwise direction .

Tanθ =  8 / 1 = 8

θ = 83° north of east .