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Mama L [17]
3 years ago
12

Give an example of an object that has balanced forces acting on it.

Physics
2 answers:
NARA [144]3 years ago
7 0
When two forces are the same strength but acting opposite direction they are called balanced forces again tug-of-war is a perfect example if the people on each side of the rope are pulling with the same strength but it opposite direction the forces are balanced the result is no motion
Gnesinka [82]3 years ago
4 0
If the forces on an object are balanced (or if there are no forces acting on it), this is what happens:

a stationary object stays still
a moving object continues to move at the same speed and in the same direction
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A worker on the roof of a house drops his 0.58 kg hammer, which slides down the roof at constant speed of 6.69 m/s. The roof mak
shusha [124]

Answer:

17.3 m

Explanation:

Given that,

Mass of a hammer is 0.58 kg

Velocity with which the hammer slides is 6.69 m/s at constant speed.

The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.

y=y_0+v_ot +\dfrac{1}{2}gt^2

Putting all the values,

0=18.2+6.69t-\dfrac{1}{2}\times 9.8t^2\\\\-4.9t^2+6.69t+18.2=0\\\\t=\dfrac{-6.69+\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}, \dfrac{-6.69-\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}\\\\t=-1.36\ s\ \text{and}\ t=2.72\ s

Neglecting negative value,

To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.

d=2.72\times 6.69\times \cos(18)\\\\d=17.3\ m

3 0
3 years ago
A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming
omeli [17]

Answer:

12.32 m/s

Explanation:

Using the formula of maximum height of a projectile,

H = u²sin²Ф/2g................... Equation 1

Where H = maximum height, u = initial velocity, Ф = angle of projection, g = acceleration due to gravity

make u the subject of the equation

u = √(2Hg/sin²Ф)............ Equation 2

Given: H = 2.3 m, Ф = 33°, g = 9.8 m/s²

Substitute into equation 2

u = √[(2×2.3×9.8)/sin²33°]

u =√ [45.08/(0.545)²]

u = 45.08/0.297

u = √(151.785)

u = 12.32 m/s

3 0
3 years ago
5) help plz I need help<br> I don't know if I am right so if I am not can you plz help me
seraphim [82]

the answer is waning Gibbous

The Waning Gibbous is an intermediary Moon phase. It starts right after the Full Moon, and it lasts until the Third Quarter.

7 0
3 years ago
Read 2 more answers
sketch a graph of position vs. time for a person starting 0.4 m away and standing still. Include an explanation of your predicti
Korvikt [17]

Answer:

Straight line parallel to time axis.

Explanation:

The slope of the position time graph gives the velocity.

As the man is still, that means the velocity is zero. So, the slope of the graph is zero. It is a straight line parallel to time axis.

5 0
3 years ago
Studying neutrinos helped to explain how our Sun works but led to changes in theories of particle physics, how is this process c
julsineya [31]

Explanation:

Yes,  evidently, the process is consistent with the scientific process because in scientific process falsification and modification are two very important traits. So this new concept have modified the existing theories.

Through the modification a theory is adjusted without undermining other discovering made through the theory's prediction.

There are many other evidences that prove this fact for example Einstien's Theory of relativity also changes the existing concepts.

3 0
2 years ago
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