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3 years ago

Is directly proportional to the length and resistivity of the conductor.

Physics

2 answers:

aliya0001 [1]3 years ago

8 0

Answer:

B) resistance

Explanation:

the resistance of a wire is proportional to its length, and inversely proportional to its cross-sectional area.

Andrews [41]3 years ago

4 0

The resistance of conductor is directly proportional to length and resistivity.

Answer: Option B

<u>Explanation: </u>

Resistance is present in an electrical object or rather introduced to counter check the flow of the current. It is similar to the mechanical friction in the conceptualization of its existence and effect.

It is directly proportional to the length of the electric circuit. It is being measured and noted in ohm. The formula for resistance is –

$R=\rho \frac{l}{A}$

Where,

R - the Resistance of the wire,

$\rho$ - the resistivity of the wire

L - The length of the wire

A - the area of cross section of the wire

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Coulombs law says that the force between any two charges depends on the amount of charges and distance between them. This force is directly proportional to the magnitude of the two charges and inversely proportional to the distance between them.

$F=k\frac{|q_1| |q_2|}{r^2}$

where $q_1\hspace{1mm}and\hspace{1mm}q_2$ are charges, $r$ is the distance between them and k is the coulomb constant.

case 1:

$q_1=-e\\ q_2=+3e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||3e|}{(100pm)^2}=3ke^2\times10^8$

case 2

$q_1=-e\\ q_2=+2e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||2e|}{(100pm)^2}=2ke^2\times10^8$

case 3:

$q_1=-e\\ q_2=+e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||e|}{(200pm)^2}=0.25ke^2\times10^8$

Comparing the 3 cases:

The maximum potential force according to coulombs law is between -1 charge and +3 charge separated by a distance of 100 pm.

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3 years ago

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A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?

bezimeni [28]

Answer:

$45 J$

Explanation:

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2 years ago

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Answer:

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2 years ago

The question states: two large, parallel conducting plates are 12cm

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Answer:

1. 24375 N/C

2. 2925 V

Explanation:

d = 12 cm = 0.12 m

F = 3.9 x 10^-15 N

q = 1.6 x 10^-19 C

1. The relation between the electric field and the charge is given by

F = q E

So, $E=\frac{F}{q}$

$E=\frac{3.9 \times 10^{-15}}{1.6 \times 10^{-19}}$

E = 24375 N/C

2. The potential difference and the electric field is related by the given relation.

V = E x d

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By substituting the values, we get

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