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2 years ago

What is osazone process?

Chemistry

2 answers:

Leona [35]2 years ago

6 0

Osazones are a class of carbohydrate.

Osazones formation test involves the reaction of a reducing sugar with excess of phenylhydrazine when kept at boiling temperature.

The reaction involves formation of a pair of phenylhydrazone functionalities, concomitant with the oxidation of the hydroxymethyl group in alpha carbon.

hope it helped a bit :-)

Lynna [10]2 years ago

4 0

Osazones are a class of carbohydrate derivatives found in organic chemistry formed when sugars are reacted with excess of phenylhydrazine. The famous German chemist Emil Fischer developed and used the reaction to identify sugars whose stereochemistry differed by only one chiral carbon

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When it acts as a base, which atom in hydroxylamine accepts a proton?

Rashid [163]

The oxygen atom accepts the proton. The oxidation number of O is -2, meaning that there are two unshared electrons in the valence shell; In the ClO- ion, one of these is shared with the Cl- ion, leaving an unshared electron on the oxygen atom, which is what the hydrogen atom shares its electron with, becoming the proton accepted by the O atom.

6 0

3 years ago

A large container holds 2 liters of water. 45.0 grams of NaCl is added to the container. What is the molarity of sodium chloride

djverab [1.8K]

Answer:

THE MOLARITY OF SODIUM CHLORIDE IN THE CONTAINER IS 0.3846 M.

Explanation:

Molarity of a solution is the number of moles of solute per dm3 of solution.

Mass concentration = Molar concentration * Molar mass

1. calculate the mass concentration;

Mass conc. = 45 g in 2 L

= 45 g in 2 dm3

In 1 dm3, the mass will be 45 / 2

= 22.5 g/dm3 of NaCl.

2. Calculate the molar mass;

(Na = 23, Cl = 35.5)

Molar mass = ( 23 + 35.5 ) g/mol

Molar mass = 58.5 g/mol

3. calculate the molarity

Molarity = mss concentration / molar mass

Molarity = 22.5 g/dm3 / 58.5 g/mol

Molarity = 0.3846 mol/dm3 of NaCl.

The molarity of sodium chloride in the container is 0.3846 mol/dm3

4 0

2 years ago

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular

mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

$\frac{actual yield}{theoretical yield} .100$

Where the actual yield is how much product was obtained, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is how much product could be obtained with the given reactants theoretically, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

$\frac{actual yield}{theoretical yield} .100$

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

5 0

3 years ago

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What is the Si ( metric) for distance? A.meters B.inches C.feet D.kilometers

bixtya [17]

A.meter is the is the answer to the problem you and and if you need to know why then type back

7 0

2 years ago

Read 2 more answers

How are vibrations different between bigger sizes rubber bands and smaller sized rubber bands?

arlik [135]

Assuming the kind of vibration you are talking about is the kind where you stretch the rubber band between two points and then "twang" it, then the answer is fairly complex. What happens when you cause the vibrations to start is you make something called a "standing wave". In a standing wave, each particle in the rubber band has a certain amount of energy which causes it to move backwards and forwards, the particles with more energy have a larger "amplitude" (how much they move), and of course the particles with less energy have a smaller amplitude. Now a standing wave has two main components: The amplitude, and the frequency. The amplitude of the whole wave refers to the largest amplitude any particles has. The frequency refers to how often it takes for one of the particles to move between the two furthest away points it can be.
To compare rubber bands, you must remember to keep certain things constant. If you're looking at their vibrations, the amount of energy you use to "twang" the rubber band should be the same each time you twang it (which is the same as applying the same force each time you twang it).

A larger rubber band has more area over which to spread the energy, as well as it has more mass for the energy to move, so the vibrations will have smaller amplitudes, and smaller frequencies, overall vibrating less and with smaller vibrations.

5 0

3 years ago