Answer:
Determine how many formula units are in 2.35 moles of lithium phosphite?
Explanation:
After reading the sources provided write a 250 word summary on the contributions of West Virginians to the war effort.What are the dimensions of the product? 2 6 4 1 -3 0 x -3 -2 -8 2 3 5 1 x 2 2 x 2 3 x 2 3 x 3Can somebody help me with this pleaseDetermine how many formula units are in 2.35 moles of lithium phosphite?Can someone help? It's due todayWhat main idea links all three of the article excerpts contained in th passage together? A) Taxation rates should be applied equally and fairly to all people. B A little bit of kindness goes a long way in trying to change the world. C) No one deserves to be lonely, and everyone deserves to be loved. D African-Americans had to fight long and hard to receive equal rights in America.Can somebody help me with this pleaseCan somebody help me with this pleaseAfter reading the sources provided write a 250 word summary on the contributions of West Virginians to the war effort.
A molecular size affects the rate of evaporation when the larger the intermolecular forces in a compound, the slower the evaporation rate and this correlates with temperature change.
Molecular size seems to have an effect on evaporation rates in that the larger a molecule gets or grows from a base chemical formula, its evaporation rate will get slower.
<h3>What is the molecular size?</h3>
This is a measure of the area a molecule occupies in three-dimensional space as this relates to the physical size of an individual molecule.
Hence, we can see that a molecular size affects the rate of evaporation the larger the forces, the lower the rate.
Read more about<em> molecular size</em> here:
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Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.
Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
