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dybincka [34]
3 years ago
15

How is the tesla coil used today

Physics
2 answers:
OlgaM077 [116]3 years ago
8 0
It is used to produce high voltage low current and high frequency
marshall27 [118]3 years ago
6 0
H<span>igh voltage demonstrations!</span>
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Copper has a specific heat of 387 J/kg°C. A copper bullet is moving at 950 m/s. If the bullet is suddenly stopped so that all of
Alla [95]

Answer:

1196.02 °C

Explanation:

If the kinetic energy is converted into heat,

then,

Kinetic energy of the copper = heat energy of the copper

1/2m(v²) = cm(t₂-t₁)

where m = mass of copper, v =  velocity of copper, c = specific heat capacity of copper, t₂ = final temperature of copper, t₁ = initial temperature of copper.

Since the mass of copper remains the same,

1/2v² = c(t₂-t₁)

make t₂ the subject of the equation

t₂ = 1/2(v²/c)+t₁..................... Equation 1

Given: v = 950 m/s, c = 387 J/kg°C, t₁ 30 °C

Substitute into equation 1

t₂ = 1/2(950²/387)+30

t₂ = 1196.02 °C

Hence the temperature the bullet reach before it was stopped = 1196.02 °C

8 0
3 years ago
Two blocks A and B have a weight of 11 lb and 5 lb , respectively. They are resting on the incline for which the coefficients of
Alchen [17]

Answer:

\theta=10.20^{\circ}  

\Delta l=0.10 ft    

Explanation:

First of all, we analyze the system of blocks before starting to move.

\Sum F_{x}=P_{A}sin(\theta)+P_{B}sin(\theta)-F_{fA}-F_{fB}=0  

\Sum F_{x}=11sin(\theta)+5sin(\theta)-0.16N_{A}-0.23N_{B}=0

11sin(\theta)+5sin(\theta)-0.16P_{A}cos(\theta)-0.23P_{B}cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0  

16sin(\theta)-2.91cos(\theta)=0  

tan(\theta)=0.18  

\theta=arctan(0.18)  

\theta=10.20^{\circ}  

Hence, the incline angle θ for which both blocks begin to slide is 10.20°.

Now, if we do a free body diagram of block A we have that after the block moves, the spring force must be taken into account.  

P_{A}sin(\theta)-F_{fA}-F_{spring}=0

Where:

F_{spring} = k\Delta l=2.1\Delta l

P_{A}sin(\theta)-0.16*11cos(\theta)-2.1\Delta l=0

\Delta l=\frac{11sin(\theta)-0.16*11cos(\theta)}{2.1}

\Delta l=0.10 ft    

Therefore, the required stretch or compression in the connecting spring is 0.10 ft.

I hope it helps you!

4 0
3 years ago
a tennis ball is hit upward with a tennis racket an initial velocity of 12 m/s. What will the ball's speed be when it returns to
zaharov [31]

Answer: 12 m/s

Explanation:

If we ignore air resistance, gravity alone will reduce the upward velocity to zero at the top of the flight. As gravity is a conservative force, it will return exactly the same amount of energy to the tennis ball when it returns to the original elevation.

7 0
3 years ago
khalil scored low on the intuitive function. since khalil has low intuition, which trait does khalil have a high score in
stiks02 [169]

Since khalil has low intuition, the trait khalil will have a high score in is counterintuition.

<h3>What is Intuition?</h3>

This is the process in which individuals acquire knowledge without conscious reasoning(thoughts) about it.

In Khalil's case, he scored a low mark in it which means he will most likely score a high mark in what we refer to as counterintuition which is the opposite.

Read more about Intuition here brainly.com/question/887641

7 0
3 years ago
A rock is thrown downward from a height of 207 m with an initial velocity of 5.37 m/s. Approximately how fast will it it be movi
Zolol [24]

List the known information:

x_0=207 \text{ m}\\v_0=-5.37 \text{ m/s}\\t=3.03 \text{ s}\\a=-g=-9.8 \text{ m/s}^2

Use the kinematic equation v=v_0+at.

Plug in the given values:

v=-5.37 \text{ m/s}+(-9.8 \text{ m/s}^2)(3.03 \text{ s})=-35.064 \text{ m/s}

This would be 35.064 m/s downward, or 35 m/s downward with significant figures taken into account.

4 0
3 years ago
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