Answer:
3.13cm/s²
Explanation:
Given
Initial velocity u = 3.5cm/s
Final velocity v = 8.2cm/s
Time t = 1.5secs
Required
Acceleration of the cart a
To get that, we will use the equation of motion
v = u+at
Substitute the given parameters
8.2 = 3.5+1.5a
1.5a = 8.2-3.5
1.5a = 4.7
a = 4.7/1.5
a = 3.13cm/s²
Hence the acceleration to the cart is 3.13cm/s²
Answer:
no motion means no velocity, so the y values willl always be 0 as ur time (x) value increses
Explanation:
Answer:
E = 1000 x
Explanation:
The electric potential and the electric field are related by the formula
dV = - E . dx
Bold represents vectors.
The point represents the scalar product, in this case we calculate the electric field in the x-axis and the potential is also in this axis so the scalar product is reduced to the algebraic product
E = dV /dx
Let's make the derivative
E = - 2ax
Let's replace the values
E = -2 (-500) x
E = 1000 x
That's 1/2 of what it is on the surface.
The distance between the center of the Earth and any object
on the surface is 1 Earth radius ... about 3960 miles.
Gravitational force is inversely proportional to the square of
the distance between the centers of the objects, so in order
to reduce the acceleration of gravity by 1/2, you increase the
distance by √2 .
(3960 miles) x (√2) = 5,600 miles from the center
= 1,640 miles above the surface.
Answer:
Explanation:
a) using the energy conservation equation
mgh = 0.5mv^2 + 0.5Iω^2
I(moment of inertia) (basket ball) = (2/3)mr^2
mgh = 0.5mv^2 + 0.5( 2/3mr^2) ( v^2/r^2)
gh = 1/2v^2 + 1/3v^2
gh = v^2( 5/6)
v = 
putting the values we get
solving for h( height)
h = 3.704 m apprx
b) velocity of solid cylinder
mgh = 0.5mv^2 + 0.5( mr^2/2)( v^2/r^2) where ( I ofcylinder = mr^2/2)
g*h = 1/2v^2 + 1/4v^2
g*h = 3/4v^2
putting the value of h and g we get
v= = 6.957 m/s apprx
