Answer:
![\{x=\frac{19-\sqrt{409} }{2}\ , \ x=\frac{19+\sqrt{409} }{2}\}](https://tex.z-dn.net/?f=%5C%7Bx%3D%5Cfrac%7B19-%5Csqrt%7B409%7D%20%7D%7B2%7D%5C%20%2C%20%5C%20%20x%3D%5Cfrac%7B19%2B%5Csqrt%7B409%7D%20%7D%7B2%7D%5C%7D)
Step-by-step explanation:
x² = 19x + 12
⇔ x² - 19x - 12 = 0
Calculating the discriminant :
b² - 4ac = (-19)² - 4×1×(-12) = 409
The discriminant is positive ,then the equation has two solutions.
![x=\frac{19-\sqrt{409} }{2} \ \ or\ \ x=\frac{19+\sqrt{409} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B19-%5Csqrt%7B409%7D%20%7D%7B2%7D%20%5C%20%5C%20or%5C%20%5C%20x%3D%5Cfrac%7B19%2B%5Csqrt%7B409%7D%20%7D%7B2%7D)
Is there a picture or is it just that
Answer:
The statement is false. Exterior angles are the angles created when the sides of the triangle are extended
Step-by-step explanation:
In order to find the exterior angle of a polygon, the side of the polygon is extended to go past the vertex of the polygon to form an angle adjacent and supplementary to the the interior angle of the polygon at the vertex of the polygon where the exterior angle is formed.
The sum of the exterior angle and the adjacent interior angle is equal to 180°
The exterior angle can also be described as being formed by one side of a polygon and an extension of the adjacent side to previous side of the same polygon and it can also be referred to as a turning or an external angle.
We do not see a graph above
Answer: x=9
Step-by-step explanation:
The bottom triangle that has a 40° is an isosceles triangle, therefore the other angle at the bottom right is also 40°. This leaves the top angle to be 100°.
180=40+40+x
180=80+x
x=100
Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°
180-100=∠2
80°=∠2
The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.
80=9x-1
81=9x
x=9