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trapecia [35]
3 years ago
5

Fill in the missing values to make the equations true.

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0
The main formulas of log are: 
log A + logB =log A*B
log A - logB =log A/B
log A ^p= p logA

so 
log_4(7)+log_4(5)=log_4(7*5)=log_4(35)<span>
log_8(11)-log_8(5)=log_8(11/5)
2log_9(3)=log_9(3)²</span>
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A taxi service charges an initial $5 fee , plus $2 per mile driven.
arlik [135]
Part A answer: 2x+5. x is the number of miles driven.

Part B answer: $305. Plug in 150 for x, and the equation is 2*150+5=x, x being your answer that you are looking for. Do the Order of Operations, which is PEMDAS (Parenthesis, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right.) So in other words, do 2*150 first, and you get 300. Now your equation is 300+5=x. Add 300+5, and you get 305=x. So your answer is $305.
6 0
3 years ago
Read 2 more answers
Jane walks 6 miles in 2 hours. Find the unit rate.
Viefleur [7K]
She walks 3 mph because when you divide it by 2 it will equal 

3 miles in 1 hour
7 0
3 years ago
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Determine the amount of potential energy of a 5.0 N book that is moved to three different shelves on a bookcase. The height of e
Aleks [24]

Answer:

Ep = weight x height = 5 x 1 = 5N ; 5 x 1.5 = 7.5N; 5 x 2 = 10N

Step-by-step explanation:

Hope that helps

7 0
3 years ago
If Y has a geometric distribution with probability of success p, show that the moment-generating function for Y is
butalik [34]

Answer:

  M₀ (t)  = p / e^-t -q = p (e^-t -q) ^ -1

Step-by-step explanation:

Let the random variable Y have a geometric distribution g (y;p) = pq y-¹

The m.g.f of the geometric distribution is derived as below

By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p    ( for ∑ , y varies 1 to infinity)

                   = pe^t ∑(e^tq)^y-1

                    = pe^t/1- qe^t,     where qe^t <1

In order to differentiate the m.g.f we write it as

           M₀ (t)  = p / e^-t -q = p (e^-t -q) ^ -1

 M₀` (t)  = pe^-t (e^-t -q) ^ -2  and

 M₀^n(t)  = 2pe^-2t (e^-t -q) ^ -3   - pe^-t (e^-t -q) ^ -2  

Hence

E (y) = p (1-q)-² = 1/p

E (y²) =2 p (1-q)-³ - p (1-q)-²

        = 2/p² - 1/p  and

σ² = [E (y²) -E (y)]²

     = 2/p² - 1/p - (1/p)²

      = q/p²

5 0
2 years ago
1. Complete each geometric sequence.
Arada [10]

Answer:

a. 12

b. 1080

c. 0.2

d. not enough info

e. 3

Step-by-step explanation:

a. Double each number

b. triple each number

c. divide each number by ten

d. not applicable, you need atleast three numbers for a sequence

e. half each number

Brainliest?

3 0
2 years ago
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