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LekaFEV [45]
3 years ago
8

A meteorologist measures the angle of elevation of a weather balloon as 41 degrees. A radio signal from the balloon indicates th

at it is 1503 m from his location. To the nearest meter, how high above the ground is the balloon?
Physics
1 answer:
Katena32 [7]3 years ago
8 0
This problem we can represent as right triangle where we can use basic trygonometric functions.

in this case we have largest side (hypothenuse) of the triangle and we have one angle. The angle we got is the one between side of triangle that is horizontal with the ground and the hypothenuse, meaning that we need sin function to connect relation between angle, known side lenght and unknown side lenght.

sin(alpha) = (side of triangle oposite from observed angle)/(hypothenuse)

sin(41) = x/1503

x = 1503*sin41 = 986.06 meters

Answer is 986.06 meters
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You have a bowling ball with a mass of 4kg. You throw it with an acceleration of 10 m/s/s. With how much force will it hit the p
Eddi Din [679]

Answer:

<h3>The answer is 40 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 4 kg

acceleration = 10 m/s²

So we have

force = 4 × 10

We have the final answer as

<h3>40 N</h3>

Hope this helps you

6 0
4 years ago
The force F1, 10.0N acts at 10.0cm. What is the magnitude of the torque due to F1 about an axis through Point A perpendicular to
Nookie1986 [14]
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution. Feel free to ask more question. 

<span>torque = rF
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4 0
3 years ago
When the Apollo 11 lunar module Eagle lands on the moon it comes to a stop 10m above the surface of the moon. The last 10m it fr
Scrat [10]

Answer:

i) 3.514 s, ii) 5.692 m/s

Explanation:

i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.

as the equation says for free-falling

h = ut +0.5gt^2

Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)

initial velocity u = 0

10 = 0.5×1.62t^2

t = 3.514 seconds

Therefore, it takes t = 3.514 seconds for the Eagle to touch down.

ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon

v = u + gt

v = 0+ 1.62×3.514

v= 5.692 m/s

7 0
3 years ago
The breaking car had 10,000 J of kinetic energy before breaking after breaking it had 2000 J of kinetic energy. How much thermal
WINSTONCH [101]

Answer:

8000J

Explanation:

The kinetic energy of the car lost during breaking are converted to thermal energy and are gained by the brakes.

Kinetic energy loss by car = thermal energy gained by brakes.

∆K.E = ∆T.E ....1

The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

Initial K.E = K.E1 = 10000J

Final K.E = K.E2 = 2000J

∆K.E= 10000J - 2000J = 8000J

From equation 1,

∆K.E = ∆T.E

∆T.E = 8,000J

thermal energy gain by brakes = 8,000J

8 0
3 years ago
Imagine an advanced civilization living on a planet orbiting at a distance of 10 AU (1.5 billion kilometers) from a close binary
aksik [14]

Answer:

Civilization's planet is most likely to be doomed because within the next million years the red giant star will possibly supernova.

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Civilization's planet is most likely to be doomed because within the next million years the red giant star will possibly supernova. The supernova is the bursting of the star that has reached its end life. This leads to release of massive amount of energy, which can be more than the heat and energy released by the sun.

6 0
4 years ago
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