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Semenov [28]
2 years ago
14

Two skaters, one with mass 52.5 kg and the other with mass 26.3 kg, stand on an ice rink holding a pole with a length of 5.00 m

and a negligible mass. Starting from the ends of the pole, the skaters pull themselves along the pole until they meet. How far will the 26.3 kg skater move?
Physics
1 answer:
Marizza181 [45]2 years ago
5 0

Answer: 10.02m

Explanation: Given

M1 = 26.3kg

M2 = 52.5kg

d = 5m

If the systems centre of mass does not change, the two skaters will definitely meet at the centre of mass.

If the 26.3kg skater is a m away from the centre of the mass, then the 52.5kg skater is (5-a) m away from the centre of the mass. Thus,

M1a + M2(5-a) = 0

26.3a + 52.5(5-a) = 0

26.3 a + 262.5 - 52.5a = 0

-26.2a + 262.5 = 0

26.2a = 262.5

a = 262.5/26.2

a = 10.02m

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A transformer consists of a 500 turn primary coil and a 2000-turnsecondary coil. If the current in the secondary is 3.0A, what i
Neporo4naja [7]

Answer:

The correct solution will be "12.0 A".

Explanation:

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By using the transformer formula, we get

⇒ \frac{N_p}{N_s}  =\frac{I_s}{I_p}

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On substituting the given values, we get

⇒      =3.0 \ A\times \frac{2000}{500}

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8 0
3 years ago
The speed of sound in air is 345 m/s. A tuning fork vibrates above the open end of a sound resonance tube. If sound waves have w
Delvig [45]

To develop this problem it is necessary to apply the concept of Frequency based on speed and wavelength.

According to the definition the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

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Replacing

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f = 547.61Hz

Therefore the frequency of the tuning fork is 547.61Hz

6 0
2 years ago
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