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Crazy boy [7]
3 years ago
14

The force F1, 10.0N acts at 10.0cm. What is the magnitude of the torque due to F1 about an axis through Point A perpendicular to

the page? Is it clockwise,or is it counterclockwise?
Physics
1 answer:
Nookie1986 [14]3 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution. Feel free to ask more question. 

<span>torque = rF
= 0.1(10)
=1 Nm</span>
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A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat
N76 [4]

Answer:

p_k=\sqrt{p_x^2+p_y^2}}

Explanation:

Apply the momentum in each direction knowing that the impact is at the same time for the pieces so

p_x=m_1*v_1

p_x=200g*2.0m/s=0.4kgm/s

p_y=m_2*v_2

p_y=235g*1.5m/s=0.3525kgm/s

So the momentum in the other piece can be find knowing that

p_x^2+p_y^2=p_k^2

So:

p_k=\sqrt{p_x^2+p_y^2}}

p_k=\sqrt{0.4^2+0.3525^2}}=\sqrt{0.2842 kg^2*m^2/s^2}

p_k=0.5331kg*m/s

To find the velocity knowing the mass

p_k=m_k*v_k

v_k=\frac{p_k}{m_k}=\frac{0.5331 kg*m/s}{0.10kg}

v_k=5.331 m/s

4 0
3 years ago
a rugby player tackles another player. in terms of kinetic energy and work done, why is it more difficult to tackle a heavier pl
matrenka [14]
The weight of the heavier player bakes it a lot harder to push him or do work because of the net force gravity<span />
6 0
3 years ago
Read 2 more answers
A solid conducting sphere with radius RR that carries positive charge QQ is concentric with a very thin insulating shell of radi
svetlana [45]

Answer:

E=0 at r < R;

E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}} at 2R > r > R;

E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}} at r >= 2R

Explanation:

Since we have a spherically symmetric system of charged bodies, the best approach is to use Guass' Theorem which is given by,

\int {E} \, dA=\frac{Q_{enclosed}}{\epsilon} (integral over a closed surface)

where,

E = Electric field

Q_{enclosed} = charged enclosed within the closed surface

\epsilon = permittivity of free space

Now, looking at the system we can say that a sphere(concentric with the conducting and non-conducting spheres) would be the best choice of a Gaussian surface. Let the radius of the sphere be r .

at r < R,

Q_{enclosed} = 0 and hence E = 0 (since the sphere is conducting, all the charges get repelled towards the surface)

at 2R > r > R,

Q_{enclosed} = Q,

therefore,

E\times4\pi r^{2}=\frac{Q_{enclosed}}{\epsilon}      

(Since the system is spherically symmetric, E is constant at any given r and so we have taken it out of the integral. Also, the surface integral of a sphere gives us the area of a sphere which is equal to 4\pi r^{2})

or, E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}

at r >= 2R

Q_{enclosed} = 2Q

Hence, by similar calculations, we get,

E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}

4 0
4 years ago
Which forces are shown on a free body diagram?
notsponge [240]

Answer:

What is a Free Body Diagram?

The free body diagram helps you understand and solve static and dynamic problem involving forces. It is a diagram including all forces acting on a given object without the other object in the system. You need to first understand all the forces acting on the object and then represent these force by arrows in the direction of the force to be drawn.

Explanation:

5 0
3 years ago
Question 36 of 45
Setler [38]

Answer: vibrate

Explanation:

The object in air can be particular objects or substances.

Sound is actually vibration of waves through a medium. The medium can be liquid, solid or gas.

Therefore, the one word that will complete and make the sentence to make sense is ' vibrate '

7 0
4 years ago
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