What will eventually happen as the earth's core cools down down over billions of year?

2 answers:

8 0

The liquid outer core would solidify likely at the area of the greatest pressure, at the inner core boundary. This may have two consequences for the core mantle coupling, the angular momentum of the inner core would increase while taking up the angular momentum of the solidifying outer core and perhaps that the reduced convection in the liquid outer core could weaken the magnetic coupling.

Because the increased momentum requires more torque force from the hypothetically weakening magnetic forces in the outer core, the difference in precession between inner core and mantle may increase hypothetically, which could result in greater misalignment of the inner core and mantle spin axes.
This is likely to generate unusual flows in the liquid outer core with all kind of unpredictable effects. One of them might be increased friction and hence conversion of rotational energy into heat, which would potentially heat up the core again??

zysi [14]2 years ago

4 0

We all die. That's the end of that folks

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Do parts a, b and c

Leona [35]

Answer:- (a)The pH of the buffer solution is 3.90.

(b) the pH of the solution after addition of HCl would be 3.60.

Solution:- (a) It is a buffer solution so the pH could easily be calculated using Handerson equation:

$pH=Pka+log(\frac{base}{acid})$

pKa can be calculated from given Ka value as:

$pKa=-logKa$

$pKa=-log(6.3*10^-^5)$

pKa = 4.20

let's plug in the values in the Handerson equation:

$pH=4.20+log(\frac{0.025}{0.05})$

pH = 4.20 - 0.30

pH = 3.90

The pH of the buffer solution is 3.90.

(b) Let's say the acid is represented by HA and the base is represented by $A^-$ .

Original mili moles of HA from part a = 0.05(100) = 5

original mili moles of $A^-$ from part a = 0.025(100) = 2.5

mili moles of HCl that is $H^+$ added = 0.100(10.0) = 1

This HCl reacts with the base present in the buffer to make HA as:

$A^-+H^+\rightarrow HA$

Total mili moles of HA after addition of HCl = 5+1 = 6

mili moles of base after addition of HCl = 2.5-1 = 1.5

Let's plug in the values in the Handerson equation again. Here, we could use the mili moles to calculate the pH. The answer remains same even if we use the concentrations also as the final volume is same both for acid and base.

$pH=4.20+log(\frac{1.5}{6})$