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3 years ago

Erosion piles up in low places to form:

Physics

2 answers:

beks73 [17]3 years ago

7 0

Soil and sand
Erosion is the movement of sand or sand particles caused by the fires of the wind

Olegator [25]3 years ago

6 0

Answer:

soil and sand

Explanation:

hope it's helpful

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What happens to a current when the electric field in the wire increase

Gnom [1K]

Answer:

If the voltage is increased then the electric field is higher, and electron velocity (average) is proportional to this field. Then you have an increase in speed. And current is total charge passing per time unit, so current is proportional to velocity value of charge (and to voltage in resistors and wire).

Explanation:

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4 years ago

The garcias like to keep their 40.0 watts front prch light on at night to welcome visitors. if the light is on from 6pm until 7a

Gnesinka [82]

Answer:

For 1 week total cost will be equal to 0.2912

Explanation:

We have given power P = 40 watt

Light is on from 6 pm to 7 am

So total time = 13 hours

We know that energy is given by

$Energy=power\times time$

So energy will be $E=40\times 13=520watt-hour=0.520Kwh$

We have given cost per KWh is 0.08

So total cost per day will be = 0.08 ×0.520 = 0.0416

For 1 week that is for 7 day total cost will be = 7×0.0416 = 0.2912

6 0

4 years ago

The 2-kg collar is attached to a spring that has an un-stretched length of 3.0 m. If the collar is drawn to point B and releases

Bezzdna [24]

Complete Question

The image for this question is shown on the first uploaded image

Answer:

$v = 3.4 \ m/s$

Explanation:

From the question we are told that

The mass of the collar is $m = 2 \ kg$

The original length is $L = 3.0 \ m$

The spring constant is $k = 3.0 \ N/m$

Generally the extension of the spring is mathematically evaluated as

$e = 4 -3 = 1 \ m$

Now with Pythagoras theorem we can obtain the length from A to B as

$AB = \sqrt{5 ^2 + 4^2}$

$AB = 6.4 \ m$

The extension of the spring at B is

$e_b = 6.4 - 3 = 3.4 \ m$

According to the law of energy conservation

The energy stored in the spring at point A + the kinetic energy of the spring = The energy stored on the spring at B

$\frac{1}{2} * k * e + \frac{1}{2} * m* v^2 = \frac{1}{2} * k * e_b$

substituting values

$\frac{1}{2} * 3 * 1^2 + \frac{1}{2} * 2* v^2 = \frac{1}{2} * 3 * 3.4^2$

=> $v = 3.4 \ m/s$

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4 years ago

Perfect Elastic Collisions

ira [324]

What is the quation?

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3 years ago

An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) what is its angular acceleration in rad/s2 ? (b) what i

MissTica

(a) The angular acceleration is given by:

$\alpha=\frac{\omega_f-\omega_i}{\Delta t}$

where

$\omega_f$ is the final angular velocity

$\omega_i$ is the initial angular velocity

$\Delta t$ is the time interval

Let's convert the angular velocities in rad/s and the time in seconds:

$\omega_f=100000 \frac{rev}{min}=100000 \frac{rev}{min} \frac{2 \pi rad/rev}{60 s/min}=10467 rad/s$

$\omega_i=0$

$\Delta t=2.00 min \cdot 60 \frac{s}{min} = 120 s$

Substituting the numbers into the equation, we find the angular acceleration:

$\alpha=\frac{10467 rad/s}{120 s}=87.2 rad/s^2$

(b) The tangential acceleration is given by the product between the angular acceleration and the distance of the point from the axis of rotation. In this case, the distance is

$r=9.5 cm=0.095 m$

Therefore the tangential acceleration is

$a=\alpha r=(87.2 rad/s^2)(0.095 m)=8.3 m/s^2$

(c) The radial acceleration (also known as centripetal acceleration) is given by the product between the square of the angular velocity and the distance from the axis of rotation:

$a=\omega^2 r=(10467 rad/s)^2(0.095 m)=1.04 \cdot 10^7 m/s^2$

6 0

4 years ago