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Degger [83]
3 years ago
10

Erosion piles up in low places to form:

Physics
2 answers:
beks73 [17]3 years ago
7 0
Soil and sand
Erosion is the movement of sand or sand particles caused by the fires of the wind
Olegator [25]3 years ago
6 0

Answer:

soil and sand

Explanation:

hope it's helpful

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What happens to a current when the electric field in the wire increase
Gnom [1K]

Answer:

If the voltage is increased then the electric field is higher, and electron velocity (average) is proportional to this field. Then you have an increase in speed. And current is total charge passing per time unit, so current is proportional to velocity value of charge (and to voltage in resistors and wire).

Explanation:

5 0
4 years ago
The garcias like to keep their 40.0 watts front prch light on at night to welcome visitors. if the light is on from 6pm until 7a
Gnesinka [82]

Answer:

For 1 week total cost will be equal to 0.2912

Explanation:

We have given power P = 40 watt

Light is on from 6 pm to 7 am

So total time = 13 hours

We know that energy is given by

Energy=power\times time

So energy will be E=40\times 13=520watt-hour=0.520Kwh

We have given cost per KWh is 0.08

So total cost per day will be = 0.08 ×0.520 = 0.0416

For 1 week that is for 7 day total cost will be = 7×0.0416 = 0.2912

6 0
4 years ago
The 2-kg collar is attached to a spring that has an un-stretched length of 3.0 m. If the collar is drawn to point B and releases
Bezzdna [24]

Complete Question

The image for this question is shown on the first uploaded image

Answer:

v =  3.4 \ m/s

Explanation:

From the question we are told that

   The mass of the collar is  m =  2 \ kg

    The original length is  L =  3.0 \ m

     The spring constant is  k =  3.0 \ N/m

     

Generally the extension of the spring  is  mathematically evaluated as

        e =  4 -3 =  1 \ m

Now with Pythagoras theorem we can obtain the length from A to B as

        AB  =  \sqrt{5 ^2  + 4^2}

       AB  = 6.4 \ m

The  extension of the spring at B is  

     e_b  =  6.4 -  3 =  3.4 \ m

According to the law of energy conservation

   The energy stored in the spring at point A +  the kinetic energy of the  spring =  The  energy stored on the spring at B

So

     \frac{1}{2}  *  k * e  +  \frac{1}{2}  * m* v^2  =  \frac{1}{2}  *  k * e_b

substituting values

    \frac{1}{2}  *  3 * 1^2  +  \frac{1}{2}  * 2* v^2  =  \frac{1}{2}  *  3 *  3.4^2

=>   v =  3.4 \ m/s

8 0
4 years ago
Perfect Elastic Collisions
ira [324]
What is the quation?
7 0
3 years ago
An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) what is its angular acceleration in rad/s2 ? (b) what i
MissTica

(a) The angular acceleration is given by:

\alpha=\frac{\omega_f-\omega_i}{\Delta t}

where

\omega_f is the final angular velocity

\omega_i is the initial angular velocity

\Delta t is the time interval


Let's convert the angular velocities in rad/s and the time in seconds:

\omega_f=100000 \frac{rev}{min}=100000 \frac{rev}{min} \frac{2 \pi rad/rev}{60 s/min}=10467 rad/s

\omega_i=0

\Delta t=2.00 min \cdot 60 \frac{s}{min} = 120 s


Substituting the numbers into the equation, we find the angular acceleration:

\alpha=\frac{10467 rad/s}{120 s}=87.2 rad/s^2


(b) The tangential acceleration is given by the product between the angular acceleration and the distance of the point from the axis of rotation. In this case, the distance is

r=9.5 cm=0.095 m

Therefore the tangential acceleration is

a=\alpha r=(87.2 rad/s^2)(0.095 m)=8.3 m/s^2


(c) The radial acceleration (also known as centripetal acceleration) is given by the product between the square of the angular velocity and the distance from the axis of rotation:

a=\omega^2 r=(10467 rad/s)^2(0.095 m)=1.04 \cdot 10^7 m/s^2


6 0
4 years ago
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