Question

A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant

Answer 1

516.154 megawatts of heat are exhausted to the river that cools the plant.

By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ($Q_{out}$), in megawatts:

$Q_{out} = Q_{in} - W$

$Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W$(1)

Where:

• $\eta$ - Efficiency.
• $W$ - Electric power, in megawatts.

If we know that $\eta = 0.39$ and $W = 330\,MW$, then the energy rate exhausted to the river is:

$Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)$

$Q_{out} = 516.154\,MW$

516.154 megawatts of heat are exhausted to the river that cools the plant.

We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473