Answer:
the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
Explanation:
Given that:
The area vector of a square loop has 5 numbers of turns i.e n = 5
each with side length = 0.2 m
Current I = 2 A
uniform magnetic field = 50.0 T
Now; the magnitude of the total magnetic field B is calculated as :
B = IA
where;
I = current
A = area ( n × l²)
B = I ( n × l²)
B = 2 × 5 × 0.2²
B = 0.4 Am²
The direction of the magnetic moment is antiparallel to the area vector;
Hence ; the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
You can start this by setting up two vectors starting at the origin.
Vector 1 has coordinates of (-57,0) since in the east direction.
Vector 2 has coordinates of (0,13) because going north.
Starting from the origin, plot the two points, which will give you two sides of a triangle.
You can use pythagorean theorem to solve for the magnitude of the velocity. And you can find the angle by arctan(y/x)
Pythagorean would produce 58.46m/s
Potential Energy = Mass * Gravitational Constant * Height
What We Don't Know: Potential Energy
What We Know:
Mass
Gravitational Constant (9.8 m/s)
Height
Ep = mgh
Ep = 4 * 9.8 * 2
Ep = 78.4 Joules
The Potential Energy of the Rock is 78.4 Joules, based on the given information! Hope this helps you!
Answer:
sum of the two forces as both point to the right is a force that points to the right,
Explanation:
The force on the cast load at point Y is given by
F = q_y E
force is a vector magnitude so its result is
∑ F = Fₐ + F_b
indicate that the charge at y is negative, we analyze the direction of the force created by each charge
Charge A
as the electric field is incoming the charge is negative and as the test charge is negative both repel each other, consequently the force points to the right
Charge B
in this case the electric field lines are salient, therefore the charge is positive, consequently the force on the charge at y is attractive and points to the right
the sum of the two forces as both point to the right is a force that points to the right, that is, in the direction of the charge located at B
